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Area by total coordinates and DMD (AB 90.29)

Short answer

Double Meridian Distance method: compute DMDs, area = ½|Σ(L × DMD)| = 43849.46 m² (4.3849 ha). The coordinate method gives the same result.

Calculate the area of the traverse by total coordinates and DMD methods.

LineABBCCDDA
Latitude (m)90.29-151.00-116.10176.81
Departure (m)246.3935.00-241.55-39.84

The traverse is closed (ΣL = 0.00 and ΣD = 0.00), so the area can be found directly from the latitudes and departures.

DMD method

DMD rule (taking the meridian through the starting station):

  • DMD of the first line = departure of the first line.

  • DMD of any line = DMD of the previous line + departure of the previous line + departure of the line itself.

  • DMD of the last line = departure of the last line with opposite sign (a check).

  • Double area = Σ (latitude × DMD), and area = ½ |Σ L × DMD|.

  • DMD(AB) = D(AB) = 246.39

  • DMD(BC) = 246.39 + (246.39) + (35.00) = 527.78

  • DMD(CD) = 527.78 + (35.00) + (-241.55) = 321.23

  • DMD(DA) = 321.23 + (-241.55) + (-39.84) = 39.84

  • Check: DMD(DA) = 39.84 = −D(DA) = 39.84, so the DMDs are correct.

LineLatitude L (m)Departure D (m)DMD (m)L × DMD (m²)
AB90.29246.39246.3922246.55
BC-151.0035.00527.78-79694.78
CD-116.10-241.55321.23-37294.80
DA176.81-39.8439.847044.11
Sum0.000.00-87698.92
Area=∣−87698.92∣2=43849.46 m2\text{Area} = \frac{|-87698.92|}{2} = 43849.46\ \text{m}^2

Coordinate method

Taking the first station as the origin (N = 0, E = 0) and adding latitudes and departures successively gives the total coordinates. The area is

2A=∑Ni (Ei+1−Ei−1)2A = \sum N_i\,(E_{i+1} - E_{i-1})
StationN (m)E (m)E(next) − E(previous)N × (E(next) − E(previous))
A0.000.00206.550.00
B90.29246.39281.3925406.70
C-60.71281.39-206.5512539.65
D-176.8139.84-281.3949752.57
Sum87698.92
Area=∣87698.92∣2=43849.46 m2\text{Area} = \frac{|87698.92|}{2} = 43849.46\ \text{m}^2

Both methods agree.

Answer: Area = 43849.46 m² (4.3849 ha).

✓ Answer checked by Claude Opus 5.5 (high effort)

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