- 2071 Shrawan · 5+2 marks
CM rejection condition; isolation amp applications
Short answer
Common-mode rejection requires matched resistor ratios: R4/R3 = R2/R1 (typically R3=R1, R4=R2), yielding Acm=0 and Vo = (R2/R1)(V2−V1). Isolation amplifier applications include medical instrumentation, high-voltage sensing, breaking ground loops, industrial process control, and protecting ADCs.
Determine the condition required to reject common mode signal in a single op-amp instrumentation amplifier with mismatched resistor. List out the applications of isolation amplifiers.
Condition to reject common-mode signal (single op-amp IA)
R1 R2
V1 ----/\/\/----+----/\/\/----+
| |
(-)\ |
>----------+--> Vo
(+)/
R3 |
V2 ----/\/\/----+---[R4]---GND
Step 1, output by superposition:
V+ = V2 · R4/(R3 + R4)
Vo = (1 + R2/R1)·V+ − (R2/R1)·V1
= [R4(R1 + R2) / (R1(R3 + R4))]·V2 − (R2/R1)·V1
Step 2, apply a pure common-mode input, V1 = V2 = Vcm:
Vo = Vcm [ R4(R1 + R2)/(R1(R3 + R4)) − R2/R1 ]
= Vcm (R1R4 + R2R4 − R2R3 − R2R4) / (R1(R3 + R4))
= Vcm (R1R4 − R2R3) / (R1(R3 + R4))
So the common-mode gain is:
Acm = (R1R4 − R2R3) / [R1(R3 + R4)]
Step 3, condition for rejection. Acm = 0 requires R1R4 = R2R3, that is:
R4/R3 = R2/R1 (resistor ratios matched)
Usually R3 = R1 and R4 = R2. Then:
Vo = (R2/R1)(V2 − V1), Ad = R2/R1, CMRR → ∞
With mismatched resistors, Acm ≠ 0 and CMRR = Ad/Acm is finite. Even a 1 % mismatch limits CMRR to about 40 dB. For this reason the resistors are trimmed (for example R4 made adjustable) or laser-trimmed in IC form.
Applications of isolation amplifiers
- Medical electronics (ECG, EEG, patient monitoring): protect the patient from leakage and fault currents
- High-voltage sensing in power electronics, motor drives and power systems
- Breaking ground loops between remote sensors and the data acquisition system
- Industrial process control: thermocouples and 4–20 mA loops at high common-mode voltage
- Protecting low-voltage control or computer circuits from high-voltage transients. They are also used in nuclear and chemical plant instruments.
✓ Answer checked by Claude Opus 5.5 (high effort)
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