- 2075 Baisakh · 5+3 marks
Losses in magnetic materials, reduction
Short answer
Alternating flux causes hysteresis loss (P_h ∝ B_max^1.6 f V) reduced by silicon steel with narrow loop, and eddy current loss (P_e ∝ B_max² f² t² V) reduced by laminating core and using high-resistivity material.
Explain the losses which occur when magnetic materials are subjected to an alternating flux. How can we reduce these losses practically?
Two losses occur in a magnetic core carrying alternating flux: hysteresis loss and eddy current loss. Together they are called the core (iron) loss.
Hysteresis loss
- Each cycle of flux reversal turns the magnetic domains of the core against internal friction. The energy used is lost as heat.
- It equals the area of the B–H loop multiplied by the volume and the frequency.
- Pₕ = ηₕ B_max^1.6 f V (Steinmetz's law), in watts.
Eddy current loss
- The alternating flux induces emf in the core itself, which drives circulating currents. These produce I²R loss.
- Pₑ = kₑ B_max² f² t² V, in watts, where t is the lamination thickness.
- Since the loss varies as f² and t², thin laminations are very effective.
Both depend on B_max and frequency, so they are present in the core of every transformer, motor and generator, and they do not change much with load.
Practical reduction
| Loss | Method of reducing |
|---|---|
| Hysteresis | Use silicon steel (3–4 % Si) or other soft magnetic alloys with a narrow B–H loop |
| Hysteresis | Anneal and use cold-rolled grain-oriented (CRGO) steel |
| Hysteresis | Do not operate at too high a B_max |
| Eddy current | Build the core from thin laminations (0.35–0.5 mm) |
| Eddy current | Insulate each lamination with varnish or oxide coating |
| Eddy current | Use material of high resistivity (silicon raises it) |
| Eddy current | Use ferrite or powdered-iron cores at high frequency |
✓ Answer checked by Claude Opus 5.5 (high effort)
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