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Constant flux from no load to full load

Short answer

Primary voltage V1 ≈ E1 = 4.44 f N1 φm; since V1 and f are fixed, φm is practically constant. Also, load current's mmf is balanced by primary load component N1 I1' = N2 I2, leaving net core mmf unchanged. Thus flux remains nearly constant from no-load to full-load.

The flux in transformer remains practically constant from no load to full load. Justify the statement.

The core flux of a transformer is fixed by the applied primary voltage, not by the load. Therefore it stays practically constant from no load to full load.

Reason 1: voltage balance in the primary

V1=E1+I1Z1≈E1=4.44fN1ϕmV_1 = E_1 + I_1Z_1 \approx E_1 = 4.44fN_1\phi_m

The primary impedance drop I1Z1I_1Z_1 is only 1 to 3% of V1V_1 at full load. Since the supply voltage V1V_1 and frequency ff are constant, ϕm=V14.44fN1\phi_m = \dfrac{V_1}{4.44fN_1} stays practically constant.

Reason 2: mmf balance

When a load current I2I_2 flows, its mmf N2I2N_2I_2 tends to reduce the flux. The primary current immediately increases by I1′I_1', so that

N1I1′=N2I2N_1I_1' = N_2I_2

The net mmf in the core is then again N1IμN_1I_\mu, the no-load value, so the flux does not change.

Conclusion: the only change in flux comes from the small primary impedance drop I1Z1I_1Z_1, which is about 1 to 3% at full load. Because the flux is constant, the core (iron) loss is constant at all loads, and the core loss measured at no load can be taken as the core loss at full load.

✓ Answer checked by Claude Opus 5.5 (high effort)

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