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Equivalent circuit of 5 kVA 200/400 V transformer

Short answer

From OC test at 200 V, 1.25 A, 150 W, shunt referred to primary: R0 = 266.67 Ω, X0 = 200 Ω. From SC test at 20 V, 12.5 A, 175 W referred to primary: R01 = 0.28 Ω, X01 = 0.286 Ω, Z01 = 0.4 Ω.

The O.C. and S.C. test data are given below for a single phase, 5 kVA, 200V/400V, and 50 Hz transformer. O.C. test from LV side: 200 V, 1.25 A, 150 W S.C. test from HV side: 20 V, 12.5 A, 175 W Calculate the equivalent circuit parameters referred to primary side and draw the equivalent circuit.

Method. The no-load (OC) test gives the shunt branch: cos⁡ϕ0=P0V0I0\cos\phi_0 = \frac{P_0}{V_0 I_0}, Iw=I0cos⁡ϕ0I_w = I_0\cos\phi_0, Iμ=I0sin⁡ϕ0I_\mu = I_0\sin\phi_0, R0=V0IwR_0 = \frac{V_0}{I_w}, X0=V0IμX_0 = \frac{V_0}{I_\mu}. The SC test gives the series branch: Z=VscIscZ = \frac{V_{sc}}{I_{sc}}, R=PscIsc2R = \frac{P_{sc}}{I_{sc}^2}, X=Z2−R2X = \sqrt{Z^2 - R^2}. Values found on one side are moved to the other side by multiplying by the square of the voltage ratio.

Primary = LV side (200 V). Rated HV current =5000/400=12.5= 5000/400 = 12.5 A, so the SC test is at full load. Factor HV to LV: (200400)2=0.25\left(\frac{200}{400}\right)^2 = 0.25.

OC test (LV): 200 V, 1.25 A, 150 W

cos⁡ϕ0=150200×1.25=0.6,sin⁡ϕ0=0.8Iw=1.25×0.6=0.75 A,Iμ=1.25×0.8=1.0 AR0=2000.75=266.67 Ω,X0=2001.0=200 Ω\begin{aligned} \cos\phi_0 &= \frac{150}{200 \times 1.25} = 0.6, \quad \sin\phi_0 = 0.8 \\ I_w &= 1.25 \times 0.6 = 0.75\ \text{A}, \quad I_\mu = 1.25 \times 0.8 = 1.0\ \text{A} \\ R_0 &= \frac{200}{0.75} = 266.67\ \Omega, \quad X_0 = \frac{200}{1.0} = 200\ \Omega \end{aligned}

These are already on the primary (LV) side.

SC test (HV): 20 V, 12.5 A, 175 W

Z02=2012.5=1.6 Ω,R02=17512.52=1.12 ΩX02=1.62−1.122=1.143 Ω\begin{aligned} Z_{02} &= \frac{20}{12.5} = 1.6\ \Omega, \quad R_{02} = \frac{175}{12.5^2} = 1.12\ \Omega \\ X_{02} &= \sqrt{1.6^2 - 1.12^2} = 1.143\ \Omega \end{aligned}

Referred to primary (multiply by 0.25):

R01=1.12×0.25=0.28 ΩX01=1.143×0.25=0.286 ΩZ01=1.6×0.25=0.4 Ω\begin{aligned} R_{01} &= 1.12 \times 0.25 = 0.28\ \Omega \\ X_{01} &= 1.143 \times 0.25 = 0.286\ \Omega \\ Z_{01} &= 1.6 \times 0.25 = 0.4\ \Omega \end{aligned}

Equivalent circuit referred to primary

 I1 ->        I0                 I2'
 o-----+--------+---[ R01 ]---[ jX01 ]---o
 +     |        |                        +
     [ R0 ]  [ jX0 ]                   load
 V1    |        |                       V2'
 -     |        |                        -
 o-----+--------+------------------------o
 All values referred to primary (LV):
 R0 = 266.67 ohm, X0 = 200 ohm
 R01 = 0.28 ohm, X01 = 0.286 ohm

Answer (primary side): R0=266.67 ΩR_0 = 266.67\ \Omega, X0=200 ΩX_0 = 200\ \Omega, R01=0.28 ΩR_{01} = 0.28\ \Omega, X01=0.286 ΩX_{01} = 0.286\ \Omega.

(Note: the no-load power factor of 0.6 is unusually high for a real transformer, but the given data are used as stated.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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