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Starting shunt generator on no load and voltage build-up

Short answer

On load at start, residual EMF sends current to the load instead of the field, preventing voltage rise. Build-up: residual flux induces small EMF; field current (if aiding) strengthens flux, cumulative rise occurs until the field resistance line intersects the OCC. Conditions: residual magnetism, aiding field mmf, field resistance below critical.

Why DC shunt generator shall not be started at load? Explain the voltage build-up process of a DC shunt generator.

Why a shunt generator is not started on load

A shunt generator builds up from residual magnetism, and its field current is taken from its own terminal voltage (If=V/RfI_f = V/R_f).

  • If a load (low resistance) is connected at starting, the small residual EMF drives most of its current through the load, and the armature drop IaRaI_aR_a becomes large compared with the tiny EMF.
  • The terminal voltage applied to the field therefore stays very low, so the field current, and hence the flux, cannot grow.
  • In terms of the characteristic: with the load connected, the field gets only part of the armature current, and the effective resistance line becomes E=If[Rf+Ra(1+RfRL)]E = I_f\left[R_f + R_a\left(1 + \dfrac{R_f}{R_L}\right)\right]. For a low load resistance RLR_L (below the critical load resistance) this line is steeper than the critical-resistance line, so it cuts the OCC only near the residual voltage and the generator fails to build up.

Therefore the load switch is kept open until the generator reaches rated voltage, and only then is the load connected.

Voltage build-up process

   +---------+------o/ o----+
   |         |    switch    |
 ( G )     [Rsh]   (open)  load
   |         |              |
   +---------+--------------+
  1. Residual flux: the field poles keep a small residual magnetism. Driving the armature at rated speed induces a small EMF ErE_r (2-5% of rated).
  2. Field current starts: ErE_r drives a small current If1=Er/RfI_{f1} = E_r/R_f through the shunt field.
  3. Flux increases: if the field winding is connected so that its MMF aids residual flux, flux rises and the EMF rises to E1E_1 (read from the OCC at If1I_{f1}).
  4. Cumulative rise: E1E_1 drives a larger If2I_{f2}, giving a higher E2E_2, and so on, step by step.
  5. Stable point: the process stops where the OCC meets the field resistance line V=IfRfV = I_fR_f. Iron saturation bends the OCC, so the intersection is definite.
  E ^              Rf line
    |             /
    |            /  _____-- OCC
    |           /.-'
    |          /'  <- final voltage
    |       .'/
    |     .' /
    |   .'  /
    | .'   /
 Er +-----/----------------> If

Conditions for build-up: residual magnetism present, field MMF aiding residual flux, field resistance below critical resistance, speed above critical speed, and no (or light) load at starting.

✓ Answer checked by Claude Opus 5.5 (high effort)

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