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Specific energy, minimum value and critical flow

Short answer

Specific energy E = y + Q²/(2gA²). dE/dy = 1 − Q²T/(gA³) = 0 at critical flow (Fr=1), giving minimum E. The specific energy curve has a subcritical upper limb and supercritical lower limb; for E > E_min two alternate depths exist. For a rectangular channel, E_min = 1.5y_c.

Define specific energy. Prove that for a given discharge, the specific energy will be minimum when the flow in the channel is critical. Draw specific energy curve and show the alternate depths, critical specific energy, subcritical and supercritical zones.

Specific energy

Specific energy EE is the energy per unit weight of water measured with the channel bed as datum:

E=y+αV22g≈y+V22g=y+Q22gA2E=y+\frac{\alpha V^2}{2g}\approx y+\frac{V^2}{2g}=y+\frac{Q^2}{2gA^2}

It has the unit of length and, unlike the total head, it can increase or decrease along the flow.

Proof of minimum energy at critical flow

For constant QQ, EE is a function of yy only. Differentiate with respect to yy (dA=T dydA=T\,dy):

dEdy=1−Q2gA3dAdy=1−Q2TgA3\frac{dE}{dy}=1-\frac{Q^2}{gA^3}\frac{dA}{dy}=1-\frac{Q^2T}{gA^3}

For minimum EE, dE/dy=0dE/dy=0:

Q2TgA3=1  ⇒  V2g(A/T)=1  ⇒  Fr=VgDh=1\frac{Q^2T}{gA^3}=1\;\Rightarrow\;\frac{V^2}{g(A/T)}=1\;\Rightarrow\;Fr=\frac{V}{\sqrt{gD_h}}=1

Since d2Edy2=3Q2T2gA4−Q2gA3dTdy>0\dfrac{d^2E}{dy^2}=\dfrac{3Q^2T^2}{gA^4}-\dfrac{Q^2}{gA^3}\dfrac{dT}{dy}>0 for usual sections, this is a minimum. The condition Fr=1Fr=1 is critical flow. Hence the specific energy is minimum at critical flow.

For a rectangular channel: yc=q2/g3y_c=\sqrt[3]{q^2/g} and Emin=32ycE_{min}=\dfrac32y_c.

Specific energy curve

  y ^
    |                    .   upper limb: subcritical (Fr < 1),
    |                  .     approaches the line E = y
 y1 |----------------*
    |             .
    |         .
 yc |-------*  <- critical point: y = yc, E = E_min
    |         .
    |             .
 y2 |----------------*       lower limb: supercritical (Fr > 1),
    |                    .   approaches the E-axis
    +-------+--------+-------> E
          E_min      E
  • The curve has two branches for a given E>EminE>E_{min} and a single point at E=EminE=E_{min}.
  • Alternate depths: the two depths y1y_1 (subcritical, upper limb) and y2y_2 (supercritical, lower limb) have the same specific energy EE.
  • Critical depth ycy_c and EminE_{min} are at the nose of the curve.
  • Subcritical zone: y>ycy>y_c, V<gDhV<\sqrt{gD_h}, upper limb (asymptotic to the 45° line E=yE=y).
  • Supercritical zone: y<ycy<y_c, V>gDhV>\sqrt{gD_h}, lower limb (asymptotic to the EE-axis).
  • For a rectangular section the curve is a cubic: y3−Ey2+q22g=0y^3-Ey^2+\dfrac{q^2}{2g}=0.

✓ Answer checked by Claude Opus 5.5 (high effort)

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