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Specific force and conjugate depths

Short answer

Specific force F = Q²/(gA) + Aȳ, or per unit width F = q²/(g y) + y²/2. Conjugate depths are the two depths having equal specific force, one supercritical and one subcritical, before and after a hydraulic jump. The specific force curve has a lower supercritical limb, an upper subcritical limb, and a minimum at critical depth.

Develop the expression for specific force and explain the concept of conjugate depths using the specific force curve (sketch the specific force curve showing conjugate depths and the zones of subcritical, critical and supercritical flow).

Specific force (momentum function)

Specific force FF at a section is the sum of the momentum flux and the hydrostatic pressure force per unit weight of water:

F=Q2gA+AyˉF=\frac{Q^2}{gA}+A\bar y

where yˉ\bar y = depth of the centroid of the flow area below the water surface.

Development (from the momentum equation)

For a short horizontal reach (friction and the weight component negligible), the net force equals the change in momentum flux:

γA1yˉ1−γA2yˉ2=ρQ(V2−V1)=ρQ2(1A2−1A1)\gamma A_1\bar y_1-\gamma A_2\bar y_2=\rho Q(V_2-V_1)=\rho Q^2\left(\frac{1}{A_2}-\frac{1}{A_1}\right) Q2gA1+A1yˉ1=Q2gA2+A2yˉ2  ⇒  F1=F2\frac{Q^2}{gA_1}+A_1\bar y_1=\frac{Q^2}{gA_2}+A_2\bar y_2\;\Rightarrow\;F_1=F_2

For a rectangular channel of width bb (q=Q/bq=Q/b, Ayˉ=by2/2A\bar y=by^2/2), the specific force per unit width is

F=q2gy+y22F=\frac{q^2}{gy}+\frac{y^2}{2}

Conjugate (sequent) depths

For a given QQ and a value of F>FminF>F_{min}, the equation F(y)=F(y)= const has two positive roots, y1y_1 (supercritical) and y2y_2 (subcritical). These are the conjugate depths: they have the same specific force. They are the depths before and after a hydraulic jump, where energy is lost but specific force is conserved. For a rectangular channel:

y2y1=12(1+8Fr12−1)\frac{y_2}{y_1}=\frac12\left(\sqrt{1+8Fr_1^2}-1\right)

Specific force curve

  y ^
    |                    .   upper limb: subcritical
 y2 |----------------*       conjugate depth y2
    |             .
    |         .
 yc |-------*  <- F_min, critical depth
    |         .
    |             .
 y1 |----------------*       conjugate depth y1
    |                    .   lower limb: supercritical
    +-------+--------+-------> F
          F_min   F1 = F2
  • Lower limb (y<ycy<y_c): supercritical flow.
  • Nose of the curve: F=FminF=F_{min} at y=ycy=y_c, where Q2TgA3=1\dfrac{Q^2T}{gA^3}=1 (critical flow).
  • Upper limb (y>ycy>y_c): subcritical flow.
  • A vertical line at a given FF cuts the curve at the two conjugate depths. The difference in specific energy between these depths is the energy loss in the jump.

✓ Answer checked by Claude Opus 5.5 (high effort)

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