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Economics of 1-φ vs 3-φ delivery

Short answer

For same power, distance, loss and voltage, three-phase 3-wire needs only 75% of the conductor of single-phase 2-wire, since Vol3/Vol1 = 3/4. Three-phase also gives more machine output per frame and cheaper transformers and motors.

Compare the economic aspects of 1-φ and 3-φ power delivery systems. Give suitable mathematical relationship to justify the argument.

For the same power, distance, line loss and maximum voltage, a 3-phase system needs less conductor material and so costs less.

Single-phase 2-wire line

Power PP, voltage VV (between conductors), p.f. cos⁡ϕ\cos\phi, length ll, area a1a_1:

I1=PVcos⁡ϕ,W=2I12ρla1=2P2ρla1V2cos⁡2ϕa1=2P2ρlWV2cos⁡2ϕ,Vol1=2a1l=4P2ρl2WV2cos⁡2ϕ\begin{aligned} I_1 &= \frac{P}{V\cos\phi},\qquad W = 2I_1^2\frac{\rho l}{a_1} = \frac{2P^2\rho l}{a_1V^2\cos^2\phi}\\ a_1 &= \frac{2P^2\rho l}{WV^2\cos^2\phi},\qquad \text{Vol}_1 = 2a_1l = \frac{4P^2\rho l^2}{WV^2\cos^2\phi} \end{aligned}

Three-phase 3-wire line (line voltage VV)

I3=P3Vcos⁡ϕ,W=3I32ρla3=P2ρla3V2cos⁡2ϕa3=P2ρlWV2cos⁡2ϕ,Vol3=3a3l=3P2ρl2WV2cos⁡2ϕ\begin{aligned} I_3 &= \frac{P}{\sqrt3V\cos\phi},\qquad W = 3I_3^2\frac{\rho l}{a_3} = \frac{P^2\rho l}{a_3V^2\cos^2\phi}\\ a_3 &= \frac{P^2\rho l}{WV^2\cos^2\phi},\qquad \text{Vol}_3 = 3a_3l = \frac{3P^2\rho l^2}{WV^2\cos^2\phi} \end{aligned}

Comparison

Vol3Vol1=34=0.75\frac{\text{Vol}_3}{\text{Vol}_1} = \frac{3}{4} = 0.75

So 3-phase 3-wire needs only 75 % of the conductor of 1-phase 2-wire (with the same voltage between conductors).

Other economic points

Aspect1-phase3-phase
Conductor100 %75 %
Machine output per frame1≈ 1.5
Transformer cost per kVAHigherLower
MotorNeeds starting aidSelf-starting, cheaper per kW
PowerPulsatingConstant
UseSmall domestic loadsGeneration, transmission, industry

Hence 3-phase delivery is more economical for generation, transmission and distribution; 1-phase is only used for small loads tapped from the 3-phase system.

✓ Answer checked by Claude Opus 5.5 (high effort)

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