- 2072 Magh · 2 marks
cos(πn/3) with frequency increased by 2π
Short answer
Increasing the frequency by 2π gives cos((π/3+2π)n)=cos(πn/3) because 2πn is an integer multiple of 2π. The signal is unchanged; DT sinusoids whose frequencies differ by 2π are identical.
The signal x[n] = cos(πn/3) is a periodic signal. What happens if the fundamental frequency of this signal is increased by 2π?
has and period . Increase the frequency by :
because is an integer multiple of for every integer .
Nothing changes: the new signal is identical to the original, with the same samples and the same period . DT sinusoids whose frequencies differ by (or any multiple of ) are the same signal. So the frequency of a DT signal is unique only over an interval of length (e.g. or ), unlike CT signals, where a higher frequency always oscillates faster. This is the basis of aliasing in sampling.
✓ Answer checked by Claude Opus 5.5 (high effort)
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