- 2078 Chaitra · 6 marks
CU tests on overconsolidated clay
Short answer
Compute σ3′ = σ3 − u, σ1′ = σ3′ + σd. From p′–q plot, Kf line gives tanα=0.4421, a=18.7 kPa. Then sinφ′ = tanα → φ′ = 26.2°, c′ = a/cosφ′ = 20.8 ≈ 21 kN/m². Effective parameters: c′ ≈ 21 kN/m², φ′ ≈ 26°.
The series of consolidated undrained tests on undisturbed samples of an overconsolidated clay were as below. Determine the shear parameters in terms of effective stresses.
| Cell pressure (kN/m²) | 100 | 200 | 400 | 600 |
|---|---|---|---|---|
| Deviator stress at failure (kN/m²) | 300 | 410 | 610 | 850 |
| Pore water pressure (kN/m²) | -45 | -15 | 50 | 110 |
Step 1: Effective principal stresses at failure
and .
| 100 | 300 | -45 | 145 | 445 | 295 | 150 |
| 200 | 410 | -15 | 215 | 625 | 420 | 205 |
| 400 | 610 | 50 | 350 | 960 | 655 | 305 |
| 600 | 850 | 110 | 490 | 1340 | 915 | 425 |
Step 2: Envelope. Draw the four effective-stress circles and the common tangent. Alternatively, fit a straight line through the points (the line), . A least-squares fit gives:
Step 3: Parameters
Answer: kN/m² and (in terms of effective stress).
✓ Answer checked by Claude Opus 5.5 (high effort)
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