- 2071 Shrawan · 8 marks
1000 kW generator: dimensions, poles, air gap
Short answer
With 300 rpm, armature power 1029 kW, D²L=0.7447 m³, p=10 chosen from brush current limit. Square pole face gives D≈1.50 m, L≈0.33 m. Air-gap mmf 50% of armature mmf yields length ≈5.1 mm.
Find the main dimension, number of poles and length of air gap of a 1000 kW, 500 V, 30[?] rpm dc generator. Assume the specific magnetic loading Bav = 0.7 Wb/m², ampere conductor per meter = 40000, square pole face, ratio of pole arc to pole pitch is 0.7. Assume efficiency as 92% and gap contraction factor as 1.15.
Assumptions: the speed is read as 300 rpm (the digit after "30" is unclear; 300 rpm is the usual value for this problem). The air-gap mmf is taken as 50% of the armature mmf per pole (usual design value, not stated), and the limits Hz and current per brush arm A are used to choose the poles.
The main dimensions come from the output equation of a dc machine (A.K. Sawhney):
where = armature power (kW), = armature diameter, = core length (m), = speed (rps).
For a generator (Sawhney), .
Step 1:
Step 2: Number of poles
Armature current A. Lap winding, current per brush arm . Square pole face gives , so .
| (m) | (m) | (Hz) | A/brush arm | /pole | |
|---|---|---|---|---|---|
| 8 | 1.394 | 0.383 | 20 | 500 | 10 949 |
| 10 | 1.502 | 0.330 | 25 | 400 | 9 435 |
| 12 | 1.596 | 0.292 | 30 | 333 | 8 355 |
fails the brush current limit. is the smallest number that satisfies it, with low frequency and armature mmf below 10 000 A. Choose .
Step 3: Main dimensions ()
Peripheral speed m/s (safe).
Step 4: Air-gap length
Answer: Poles = 10, m, m, air gap mm.
✓ Answer checked by Claude Sonnet 5.5
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