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Circular windings and two-stepped core

Short answer

Circular windings handle short‑circuit forces as uniform hoop stress, minimise copper, and are easy to wind. Stepped cores fill the circular coil better, increasing net iron area and reducing mean turn length. For a two‑stepped (cruciform) core, optimum dimensions: a = 0.85d, b = 0.53d, giving maximum gross area 0.618d² (stacked net area ~0.56d²).

Why are windings of a transformer made into circular form? What is the advantage of using stepped cores in transformers? Derive the most economical dimension of a two-stepped core.

Why windings are circular

  • Under short circuit, radial forces on a circular coil produce uniform hoop stress, so the coil keeps its shape. Rectangular coils would deform.
  • For a given area enclosed, a circle has the smallest perimeter, so the mean length of turn, copper weight and copper loss are minimum.
  • Circular coils are easy to wind on formers and give uniform clearances and oil ducts.

Advantages of stepped cores

A square core inside a circular coil leaves much space unused. A stepped core fills the circle better.

  • For the same circumscribing diameter dd, the net iron area is larger (square 0.45d20.45d^2, cruciform 0.56d20.56d^2, 3-step 0.60d20.60d^2).
  • For the same iron area, the diameter dd and so the mean turn of the windings are smaller, saving copper and copper loss.
  • Less space wasted, so a smaller, cheaper transformer with lower leakage reactance.

Most economical dimensions of a two-stepped (cruciform) core

          <---- a ---->
          +-----------+
       +--+-----------+--+  ^
       |  |           |  |  b
       +--+-----------+--+  v
          +-----------+
     circle of diameter d

Let aa = width of the larger stamping, bb = width of the smaller one, and θ\theta the angle that the diagonal makes with the side aa. Then

a=dcos⁡θ,b=dsin⁡θa = d\cos\theta,\qquad b = d\sin\theta

Gross core area (two rectangles a×ba\times b, minus the common square b2b^2):

Agi=2ab−b2=2d2sin⁡θcos⁡θ−d2sin⁡2θ=d2(sin⁡2θ−sin⁡2θ)\begin{aligned} A_{gi} &= 2ab - b^2 = 2d^2\sin\theta\cos\theta - d^2\sin^2\theta\\ &= d^2\left(\sin2\theta - \sin^2\theta\right) \end{aligned}

For maximum area:

dAgidθ=d2(2cos⁡2θ−sin⁡2θ)=0tan⁡2θ=2  ⇒  θ=31.72∘\begin{aligned} \frac{dA_{gi}}{d\theta} &= d^2(2\cos2\theta - \sin2\theta) = 0\\ \tan2\theta &= 2 \;\Rightarrow\; \theta = 31.72^\circ \end{aligned}

So

a=dcos⁡31.72∘=0.85 db=dsin⁡31.72∘=0.53 dAgi,max=d2(sin⁡63.43∘−sin⁡231.72∘)=0.618 d2\begin{aligned} a &= d\cos31.72^\circ = 0.85\,d\\ b &= d\sin31.72^\circ = 0.53\,d\\ A_{gi,max} &= d^2(\sin63.43^\circ - \sin^2 31.72^\circ) = 0.618\,d^2 \end{aligned}

With stacking factor 0.9, net iron area Ai=0.9×0.618d2≈0.56 d2A_i = 0.9 \times 0.618d^2 \approx 0.56\,d^2. The cruciform core uses 0.618/0.785 ≈ 79% of the circle area, against 64% for a square core.

✓ Answer checked by Claude Sonnet 5.5

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