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Most economical conductor from cost data

Short answer

With CRF=0.1455, annual cost = (A+B)×CRF +9×C. Deer has the lowest total annual cost of Rs554.37 thousand/km, making it the most economical conductor because its higher capital is offset by much lower energy losses.

For the transmission line design following computations has been made. Select the most economical conductor.

ConductorA: Tower cost/km (1000 Rs.)B: Total conductor cost/km (1000 Rs.)C: Annual energy loss/km (1000 kWh)
Goat890125432
Sheep946145030
Zebra984158528
Deer910166320

Using the following data: Energy rate = Rs 9 per unit, Interest rate = 14%, Project life = 25 years. [Column C is printed as "Annual energy loss/km (1000 kW/hr.)".]

The most economical conductor is the one with the lowest total annual cost per km. This is the annual charge on the capital (towers plus conductor), spread over the project life at the given interest rate, plus the annual cost of energy lost.

Capital recovery factor

With i=14%i = 14\% and n=25n = 25 years:

CRF=i(1+i)n(1+i)n−1=0.14(1.14)25(1.14)25−1=0.14550\begin{aligned} CRF &= \frac{i(1+i)^n}{(1+i)^n - 1} \\ &= \frac{0.14(1.14)^{25}}{(1.14)^{25} - 1} = 0.14550 \end{aligned}

Annual cost of energy loss

Column C is in thousands of kWh per km per year, and the energy rate is Rs 9 per kWh. So the loss cost in thousand Rs is 9C9C. For Goat: 32×9=28832 \times 9 = 288 thousand Rs.

Comparison (per km)

ConductorCapital A+B (1000 Rs)Annual capital charge (1000 Rs)Annual loss cost (1000 Rs)Total annual cost (1000 Rs)
Goat2144311.95288599.95
Sheep2396348.61270618.61
Zebra2569373.79252625.79
Deer2573374.37180554.37

Sample calculation for Deer: (910+1663)×0.14550=374.37(910 + 1663) \times 0.14550 = 374.37, and 374.37+20×9=554.37374.37 + 20 \times 9 = 554.37 thousand Rs.

Answer: Deer is the most economical conductor, with a total annual cost of about Rs 554.37 thousand per km. Its higher capital cost is more than recovered by its much lower energy loss.

If the energy loss is instead worked as a present worth (annual loss cost ÷ CRF, added to the capital), the ranking is the same, because both methods differ only by the factor CRF.

✓ Answer checked by Claude Opus 5.5 (high effort)

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