Skip to main content

Empirical flood formula, 100 sq km catchment

Short answer

Using the rational formula with time of concentration from Kirpich's formula, intensity reduced from maximum daily rainfall, the peak discharge is approximately 110 m³/s for a 100 km² catchment.

Calculate the flood discharge using Empirical method from a catchment of area 100 sq km. The catchment has longest river of 60 km. The elevation difference of the river is 20 m. Rainfall runoff coefficient is 0.6 and maximum daily rainfall is 200 mm.

Method. Use the rational formula, with the time of concentration from Kirpich's empirical formula and the intensity from the maximum daily rainfall by the empirical reduction formula (IMD/Indian practice).

Data

A = 100 km², L = 60 km = 60 000 m, fall H = 20 m, C = 0.6, maximum daily (24 h) rainfall P = 200 mm.

Step 1: Slope and time of concentration

S=HL=2060000=3.333e−04S=\frac{H}{L}=\frac{20}{60000}=3.333e-04 tc=0.0195 L0.77S−0.385=0.0195 (60000)0.77(3.333e−04)−0.385=2032 min=33.9 ht_c=0.0195\,L^{0.77}S^{-0.385}=0.0195\,(60000)^{0.77}(3.333e-04)^{-0.385}=2032 \text{ min}=33.9 \text{ h}

Step 2: Rainfall intensity for duration tct_c

i=P24(24tc)2/3=20024(2433.9)2/3=6.62 mm/hi=\frac{P}{24}\left(\frac{24}{t_c}\right)^{2/3}=\frac{200}{24}\left(\frac{24}{33.9}\right)^{2/3}=6.62 \text{ mm/h}

Step 3: Peak flood

Q=0.278 C i A=0.278×0.6×6.62×100=110 m3/sQ=0.278\,C\,i\,A=0.278\times0.6\times6.62\times100=110 \text{ m}^3/\text{s}

Answer: flood discharge ≈ 110 m³/s. (A 100 km² catchment is larger than the usual limit of the rational method, so the result is approximate.)

✓ Answer checked by Claude Sonnet 5.5

All Engineering Hydrology chapter 6 questions →