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UH derivation from complex storms

Short answer

Separate baseflow to obtain DRH; compute net rainfall for each period. Solve the convolution equations forward: U₁ = Q₁/P₁, Uₙ = (Qₙ − Σ Pₘ Uₙ₋ₘ₊₁ for m>1) / P₁. Check that the volume equals 1 cm runoff; smooth or use least-squares if oscillations occur.

Describe the procedure of derivation of unit hydrograph from complex storms using appropriate expressions.

A unit hydrograph (UH) derived from a complex storm uses a direct runoff hydrograph (DRH) that results from several successive periods of rainfall excess of different intensity. Because the UH ordinates cannot be read off directly as in a single burst, the DRH is deconvoluted using the convolution (discrete) equation.

Basic equation

If the net rain in successive periods of duration DD is P1,P2,…,PMP_1, P_2, \dots, P_M (cm), the UH of duration DD has ordinates U1,U2,…,UNU_1, U_2, \dots, U_N, and the DRH has ordinates Q1,Q2,…,QnQ_1, Q_2, \dots, Q_n, then

Qn=∑m=1n≤MPm Un−m+1,n=M+N−1Q_n = \sum_{m=1}^{n\le M} P_m\, U_{n-m+1}, \qquad n = M+N-1

Writing it out for each ordinate:

Q1=P1U1Q2=P1U2+P2U1Q3=P1U3+P2U2+P3U1  ⋮\begin{aligned} Q_1 &= P_1U_1 \\ Q_2 &= P_1U_2 + P_2U_1 \\ Q_3 &= P_1U_3 + P_2U_2 + P_3U_1 \\ &\ \ \vdots \end{aligned}

Procedure

  1. Select a storm with several periods of rain of uniform duration DD over the whole basin, and its stream-flow record.
  2. Separate base flow from the storm hydrograph to get the DRH ordinates QnQ_n at intervals DD.
  3. Compute the rainfall excess PmP_m of each period by deducting losses (φ-index or a loss model). A period with no excess stays in the sequence as Pm=0P_m=0, because it only shifts the later periods in time.
  4. Number of UH ordinates N=n−M+1N = n - M + 1 (n = number of DRH ordinates, M = number of excess-rain periods).
  5. Solve the equations successively (forward substitution):
U1=Q1P1,U2=Q2−P2U1P1,U3=Q3−P2U2−P3U1P1, …U_1=\frac{Q_1}{P_1},\quad U_2=\frac{Q_2-P_2U_1}{P_1},\quad U_3=\frac{Q_3-P_2U_2-P_3U_1}{P_1},\ \dots
  1. Check: the area of the derived UH must equal 1 cm of runoff over the basin: ∑Ui⋅D⋅3600=A×0.01\sum U_i \cdot D\cdot 3600 = A\times 0.01 m. Adjust (smooth) the ordinates if needed.
  2. Plot the UH and, if necessary, re-compute the DRH from it to confirm that it reproduces the observed DRH.

Remarks

  • Forward substitution accumulates errors, so ordinates may oscillate or become negative. In that case the least-squares (matrix) form Q=[P]U\mathbf{Q}=[\mathbf{P}]\mathbf{U}, with U=(PTP)−1PTQ\mathbf{U}=(\mathbf{P}^T\mathbf{P})^{-1}\mathbf{P}^T\mathbf{Q}, or a trial-and-error / optimisation approach with a non-negative constraint is used (Collins' method: assume a UH, compute the DRH, correct the UH, and repeat).
  • The UH obtained from the average of several storms is more reliable.

✓ Answer checked by Claude Sonnet 5.5

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