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Bus quantities and decoupled load flow steps

Short answer

Slack bus specifies |V| and δ=0°, finds P, Q. PV bus specifies P and |V|, finds Q, δ. PQ bus specifies P, Q, finds |V|, δ. Decoupling assumes X>>R and small angle differences so P depends on δ, Q on |V|. Steps: form Ybus, flat start; compute mismatches; form J1, J4; solve for Δδ and Δ|V|; update; check Q limits; repeat.

Write down the specified and unspecified quantities of different types of buses used in load flow analysis. State the assumptions that are made in decoupled load flow analysis and also write down in brief steps for this analysis.

Specified and unspecified quantities

Bus typeSpecifiedUnspecified (found)
Slack / swing bus∣V∣\lvert V\rvert, δ\delta (= 0°)P, Q
PV / generator busP, ∣V∣\lvert V\rvert (+ Q limits)Q, δ\delta
PQ / load busP, Q∣V∣\lvert V\rvert, δ\delta

The slack bus supplies the losses and balances generation and load; a PV bus whose Q hits a limit is converted to a PQ bus.

Assumptions in decoupled load flow

  1. X≫RX \gg R for transmission lines, so Gik≪BikG_{ik} \ll B_{ik}.
  2. Angle differences across lines are small: sin⁡(δi−δk)≈0\sin(\delta_i - \delta_k) \approx 0, cos⁡(δi−δk)≈1\cos(\delta_i - \delta_k) \approx 1.
  3. So P depends mainly on δ\delta and Q mainly on ∣V∣|V|: J2=∂P/∂∣V∣≈0J_2 = \partial P/\partial|V| \approx 0 and J3=∂Q/∂δ≈0J_3 = \partial Q/\partial\delta \approx 0.

The N-R equations then split into:

ΔP=J1 Δδ,ΔQ=J4 Δ∣V∣\Delta P = J_1\,\Delta\delta,\qquad \Delta Q = J_4\,\Delta|V|

Steps

  1. Form YbusY_{bus}; flat start (δ=0\delta = 0, ∣V∣=1.0|V| = 1.0 at PQ buses, ∣V∣sp|V|^{sp} at PV buses).
  2. Calculate PiP_i for all non-slack buses and QiQ_i for PQ buses.
  3. Find mismatches ΔP\Delta P and ΔQ\Delta Q; stop if all are below tolerance.
  4. Form J1J_1 and solve Δδ=J1−1ΔP\Delta\delta = J_1^{-1}\Delta P; update δ\delta.
  5. Form J4J_4 and solve Δ∣V∣=J4−1ΔQ\Delta|V| = J_4^{-1}\Delta Q; update ∣V∣|V|.
  6. Check Q limits of PV buses; repeat from step 2.
  7. After convergence, compute slack power, line flows and losses.

✓ Answer checked by Claude Sonnet 5.5

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