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Ybus elements and line shunt effect

Short answer

For a 3-bus system, Yii is sum of all admittances at bus i (including shunt yi0), Yik = –yik. Shunt admittances from line charging add only to diagonal elements, reducing their inductive magnitude, making Ybus nonsingular, and contributing reactive generation.

With the help of suitable 3-Bus Power System Network, deduce the expression for Y-Bus Matrix elements. Also discuss how the consideration of line shunt parameter affects the Y-Bus Matrix elements.

The bus admittance matrix relates bus injected currents to bus voltages, I=YbusV\mathbf{I} = \mathbf{Y}_{bus}\mathbf{V}. Its elements are found from KCL at each bus.

3-bus network

Buses 1, 2 and 3 are connected by lines 1-2, 2-3 and 1-3. Each line is represented by a π model: series admittance yiky_{ik} and half of the line-charging admittance yik′/2=jBik/2y'_{ik}/2 = jB_{ik}/2 at each end. I1,I2,I3I_1, I_2, I_3 are injected currents.

                I2
                |
               (2)--- y20 --- ground
              /     \
        y12  /       \  y23
            /         \
 I1 --(1)--------------(3)-- I3
    |       y13         |
   y10                 y30
    |                   |
  ground              ground

 y10 = y'12/2 + y'13/2,  y20 = y'12/2 + y'23/2,  y30 = y'13/2 + y'23/2

KCL at each bus

I1=y10V1+y12(V1−V2)+y13(V1−V3)I2=y20V2+y12(V2−V1)+y23(V2−V3)I3=y30V3+y13(V3−V1)+y23(V3−V2)\begin{aligned} I_1 &= y_{10}V_1 + y_{12}(V_1 - V_2) + y_{13}(V_1 - V_3) \\ I_2 &= y_{20}V_2 + y_{12}(V_2 - V_1) + y_{23}(V_2 - V_3) \\ I_3 &= y_{30}V_3 + y_{13}(V_3 - V_1) + y_{23}(V_3 - V_2) \end{aligned}

Rearranging,

[I1I2I3]=[y10+y12+y13−y12−y13−y12y20+y12+y23−y23−y13−y23y30+y13+y23][V1V2V3]\begin{bmatrix} I_1 \\ I_2 \\ I_3 \end{bmatrix} = \begin{bmatrix} y_{10} + y_{12} + y_{13} & -y_{12} & -y_{13} \\ -y_{12} & y_{20} + y_{12} + y_{23} & -y_{23} \\ -y_{13} & -y_{23} & y_{30} + y_{13} + y_{23} \end{bmatrix} \begin{bmatrix} V_1 \\ V_2 \\ V_3 \end{bmatrix}

General expressions

Yii=yi0+∑k≠iyik,Yik=−yik (i≠k)Y_{ii} = y_{i0} + \sum_{k \ne i} y_{ik},\qquad Y_{ik} = -y_{ik}\ (i \ne k)

so that for an nn-bus system Ii=∑k=1nYikVkI_i = \sum_{k=1}^{n} Y_{ik}V_k.

  • YiiY_{ii} (self/driving-point admittance) = sum of all admittances terminating at bus ii.
  • YikY_{ik} (mutual/transfer admittance) = negative of the series admittance between ii and kk; zero if not connected.

Effect of line shunt parameters

With line charging, yi0=∑kjBik2y_{i0} = \sum_k \dfrac{jB_{ik}}{2} (plus any shunt capacitor/reactor at bus ii).

  1. Only diagonal elements change. Each YiiY_{ii} gains the term +j∑Bik/2+j\sum B_{ik}/2. Off-diagonal elements Yik=−yikY_{ik} = -y_{ik} are unchanged, because shunt branches connect a bus to ground, not to another bus.
  2. Since series admittance is inductive (negative imaginary part) and charging is capacitive (positive), the shunt term reduces the magnitude of the imaginary part of YiiY_{ii}.
  3. Without shunts, each row of YbusY_{bus} sums to zero (matrix is singular, no reference). Shunt elements give a path to ground, making YbusY_{bus} non-singular so Zbus=Ybus−1Z_{bus} = Y_{bus}^{-1} exists.
  4. In load flow, the shunt terms add reactive generation, raising voltages at light load; neglecting them is acceptable only for short lines.

✓ Answer checked by Claude Sonnet 5.5

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