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Settling tank 30 m x 3 m, 0.02 mm, SG 2.50

Short answer

Stokes' settling velocity vs = 0.0325 cm/s for 0.02 mm particles at 20°C. Detention time = H/vs = 300/0.0325 = 2.57 h. Temperature effect: lower temperature increases viscosity, reducing vs and removal efficiency; design should be based on lowest water temperature.

In continuous flow settling tank 30 m long and 3.0 meter deep, what detention time would you recommend for effective removal of 0.02 mm particles at 20°C? Assume specific gravity of particles = 2.50. Also, describe how temperature affects the removal efficiency of a sedimentation tank.

For 100 % removal in an ideal continuous-flow tank, a particle must settle the full depth during the detention time: t=H/vst = H/v_s.

Detention time

Data: d=0.02d = 0.02 mm =0.002=0.002 cm, Ss=2.50S_s = 2.50, T=20T = 20 °C, ν=0.01007\nu = 0.01007 cm²/s, H=3.0H = 3.0 m =300= 300 cm, L=30L = 30 m.

vs=981×(2.50−1)×0.002218×0.01007=0.0325 cm/sv_s=\frac{981\times(2.50-1)\times0.002^2}{18\times0.01007}=0.0325\ \text{cm/s}

Re=0.006<1Re=0.006<1, so Stokes' law is valid.

t=3000.0325=9239 s=2.57 ht=\frac{300}{0.0325}=9239\ \text{s}=2.57\ \text{h}

Horizontal velocity =L/t=3000/9239=0.325=L/t=3000/9239=0.325 cm/s (=0.19=0.19 m/min, below 0.3 m/min).

Answer: recommended detention time = 2.57 h (about 154 min).

Effect of temperature on removal

Settling velocity is inversely proportional to the kinematic viscosity: vs∝1/νv_s \propto 1/\nu. As the temperature of water falls, the viscosity rises (it is 0.01306 cm²/s at 10 °C and 0.00893 cm²/s at 25 °C), so settling is slower and fewer particles are removed in a given tank. In cold weather the detention time must be longer (or the surface area larger) for the same efficiency. Hence a tank is designed for the lowest water temperature.

✓ Answer checked by Claude Opus 5.5 (high effort)

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