- 2065 Kartik (CS I) · 6+2 marks
ASK and FSK modulators/demodulators; PSK with envelope detector
Short answer
ASK switches carrier amplitude on/off; FSK switches between two frequencies. Both can be demodulated coherently or with envelope detectors. PSK cannot be envelope-detected because its amplitude is constant for both phases, so the envelope detector output is identical and carries no information; coherent detection or DPSK is necessary.
Explain ASK and FSK modulators and demodulators with the help of block diagrams. Can PSK wave be detected using envelope detector? Explain.
ASK modulator
In Amplitude Shift Keying (on-off keying) the carrier is sent for bit 1 and switched off for bit 0: , with .
binary (unipolar NRZ) b(t) ---->(X)----> ASK
^
A cos 2 pi fc t (oscillator)
The product modulator (or simply a switch) passes the carrier only during 1s.
ASK demodulators
Coherent:
ASK -->(X)-->[integrate 0..Tb]-->[compare with Vth]--> data
^
cos wc t (carrier recovery)
Non-coherent (envelope detection):
ASK ->[BPF at fc]->[envelope det]->[comparator]-> data
The output is high when the carrier is present (1) and near zero when it is absent (0); the threshold is about half the peak.
FSK modulator
In Frequency Shift Keying bit 1 is sent at and bit 0 at .
b(t) --------------->(X)<-- cos w1 t --+
| (+)--> FSK
+-->[Inverter]---->(X)<-- cos w2 t --+
Equivalently, the polar NRZ data can drive a VCO, whose output frequency switches between and (giving continuous phase).
FSK demodulators
Coherent:
+->(X)<-cos w1 t ->[int 0..Tb]--+
FSK ---+ (-)--> l --> l>0: 1
+->(X)<-cos w2 t ->[int 0..Tb]--+ l<0: 0
Non-coherent:
+->[BPF f1]->[envelope det]--+
FSK ---+ [compare]--> data
+->[BPF f2]->[envelope det]--+
The branch with the larger envelope decides the bit. A PLL demodulator can also be used.
Can PSK be detected with an envelope detector?
No. In binary PSK, . The amplitude is for both 1 and 0; only the phase differs by :
An envelope detector responds only to amplitude, so its output is a constant for every bit and all information is lost. PSK must be detected coherently (multiply by a locally recovered carrier and integrate, the sign gives the bit), or in differential form (DPSK) by comparing each bit with the previous one.
✓ Answer checked by Claude Opus 5.5 (high effort)
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