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Square law detector limitation; envelope detector

Short answer

Square-law detector produces m²(t) distortion, requiring low modulation index; cannot recover DSB-SC. Envelope detector: diode rapidly charges capacitor to carrier peak, then capacitor slowly discharges through R_L, tracing envelope. Required: 1/f_c << R_LC << 1/W, μ≤1 to prevent ripple and diagonal clipping.

What is the limitation of square law detector for DSB-AM detection? Explain the operation of envelope detector with required diagrams and conditions.

Limitation of the square-law detector

A square-law detector passes the AM wave through a non-linear device v2=a1v1+a2v12v_2 = a_1v_1 + a_2v_1^2 and then a low-pass filter. For v1=Ac[1+kam(t)]cos⁡ωctv_1 = A_c[1+k_am(t)]\cos\omega_ct the useful low-frequency output is

vo(t)=a2Ac22[2kam(t)+ka2m2(t)]v_o(t) = \frac{a_2A_c^2}{2}\left[2k_am(t) + k_a^2m^2(t)\right]

The ka2m2(t)k_a^2 m^2(t) term is distortion (second harmonic and intermodulation of the message). The ratio of distortion to wanted signal is about ka∣m(t)∣/2k_a|m(t)|/2, so it is small only when μ\mu is small (lightly modulated, weak signals). It therefore needs low modulation depth, works only at low signal levels, and has low efficiency. For DSB-SC (no carrier) it gives only m2(t)m^2(t), so the message cannot be recovered at all.

Envelope detector

An envelope detector is a diode–RC circuit whose output follows the envelope Ac[1+μm(t)]A_c[1+\mu m(t)] of a standard AM wave.

        D
 o----->|-----+--------+-----o
 AM           |        |
 input   C  ===       > RL    v_o
              |        >
 o------------+--------+-----o

Operation

  1. In the positive half of each carrier cycle the diode is forward biased and the capacitor charges rapidly, through the small source resistance RsR_s, up to the peak value.
  2. When the input drops below the capacitor voltage the diode turns off, and CC discharges slowly through RLR_L.
  3. At the next peak the diode conducts again. The capacitor voltage thus traces the peaks, i.e. the envelope, with a small ripple at fcf_c.
  4. An RC low-pass filter removes the ripple, and a blocking capacitor removes the DC level, leaving m(t)m(t).
 Input AM          Output
 /\  /\/\  /\      _/\_   _
/\/\/\  \/\/\/  -> /    \_/
\/\/\/  /\/\/\
 \/  \/\/  \/

Conditions for correct working

  1. Fast charging: RsC≪1/fcR_sC \ll 1/f_c, so the capacitor reaches the peak in each cycle.
  2. Slow discharge between carrier peaks: RLC≫1/fcR_LC \gg 1/f_c, to keep ripple small.
  3. Fast enough to follow the message: RLC≪1/WR_LC \ll 1/W. If RLCR_LC is too large, the output cannot follow a falling envelope (diagonal clipping). For a single tone the limit is RLC≤1−μ2μ ωmR_LC \le \dfrac{\sqrt{1-\mu^2}}{\mu\,\omega_m}.
  4. No over-modulation: μ≤1\mu \le 1, otherwise the envelope crosses zero and no longer equals m(t)m(t).
  5. fc≫Wf_c \gg W, so the carrier ripple can be separated from the message.

Combined: 1fc≪RLC≪1W\dfrac{1}{f_c} \ll R_LC \ll \dfrac{1}{W}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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