- 2079 Chaitra · 8 marks
I-section purlin for industrial building
Short answer
Provide an ISMB 125 purlin with a sag rod at mid-span. The section satisfies biaxial bending, shear, and deflection; use cleat connections with two M12 bolts at each end.
Design an I-section purlin for an industrial building to support a galvanized corrugated iron sheet roof from the following data: Spacing of the trusses = 5 m Spacing of purlins = 1.5 m Inclination of main rafter to horizontal = 30° Weight of galvanized sheets taking into account laps and connecting bolts = 130 N/m² Wind load = 1 kN/m²
Approach. The purlin is a simply supported beam bent about both axes, because the loads are inclined to its principal axes. Design to IS 800:2007 (cl. 8.2 and 9.3), with loads from IS 875.
Data
- Steel Fe 410 (E250): N/mm², . Purlin span m (truss spacing); inclination of rafter (, ).
- Sag rods are provided at mid-span to restrain the purlin in the plane of the roof. The 1 kN/m² wind load is taken as the net design pressure normal to the roof (acting either towards or away from the roof). Spacing of purlins along the slope = 1.5 m; trusses at 5 m.
Loads per metre run of purlin
- Sheeting: kN/m (dead, vertical), plus the self-weight of the purlin (trial section below).
- Live load (IS 875 Part 2, roof slope above 10°): kN/m², but not less than 0.40 kN/m² on plan, so use kN/m². Per metre of purlin: kN/m (vertical).
- Wind: given wind pressure kN/m² m kN/m, acting normal to the roof.
Trial section and capacities
Try ISMB 125: , , , mm, cm⁴, cm⁴, cm³, mass 13.3 kg/m (self-weight kN/m).
Section class: and are within the plastic limits ( and ).
Load combinations and moments (IS 800 Table 4)
Normal component and tangential component (kN/m), with and , where (one sag rod at mid-span):
| Combination | (kN·m) | (kN·m) | used | |||
|---|---|---|---|---|---|---|
| 1.5(DL+LL) | +1.10 | 0.63 | 3.43 | 0.50 | 18.27 | 0.35 |
| 1.2(DL+LL+WL) | +2.68 | 0.51 | 8.37 | 0.40 | 18.27 | 0.59 |
| 1.5(DL+WL) | +2.67 | 0.24 | 8.35 | 0.19 | 18.27 | 0.52 |
| 0.9DL+1.5WL (uplift) | -2.00 | 0.15 | 6.24 | 0.11 | 11.36 | 0.59 |
For the uplift case the bottom flange is in compression and unrestrained between sag rods (), so the lateral-torsional buckling capacity is used for . The greatest ratio is 0.59 . Safe in biaxial bending.
Shear: kN kN. OK.
Deflection (unfactored wind load of 1.5 kN/m normal to the roof, limit span/150 for elastic sheeting, Table 6): mm mm. OK.
Result
Provide an ISMB 125 purlin, simply supported on the rafters, with a sag rod (12 mm) at mid-span and cleat connections with two M12 bolts at each end.
✓ Answer checked by Claude Opus 5.5 (high effort)
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