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Total energy line and hydraulic gradient line

Short answer

TEL joins total heads (p/ρg + V²/2g + z), always falls in flow direction except at pumps. HGL joins piezometric heads (p/ρg + z), lies below TEL by V²/2g. In uniform pipe parallel to TEL; rises at expansions. Sketch shows losses at entrance, friction, sudden enlargement, exit.

Explain the total energy line and the hydraulic gradient line for fluid flow through a piping system with neat sketch.

Total energy line (TEL or EGL)

The total energy line is the line joining the total heads (pρg+V22g+z)\left(\frac{p}{\rho g} + \frac{V^2}{2g} + z\right) at points along the pipe, plotted above the datum.

  • It always falls in the direction of flow (due to friction and minor losses), except where a pump adds energy.
  • It has sudden drops at entry, sudden expansion, contraction, valves and bends.

Hydraulic gradient line (HGL)

The hydraulic gradient line joins the piezometric heads (pρg+z)\left(\frac{p}{\rho g} + z\right), i.e. the levels to which water would rise in piezometers fitted along the pipe.

  • It lies below the TEL by the velocity head V2/2gV^2/2g.
  • It is parallel to the TEL in a uniform pipe; it can rise where the pipe enlarges (velocity falls).
  • Where the pipe rises above the HGL, the pressure is negative (siphon or cavitation risk).

Sketch: two reservoirs joined by a pipe with a sudden enlargement

 ===== reservoir 1
  \__  entry loss 0.5 V1^2/2g
     \___  TEL (steep in small pipe)
  HGL  \_ \___
   (V1^2/2g) \_|  drop (V1-V2)^2/2g
        \___   |____  TEL (flatter)
            \__ ^    \______
               \| HGL rises   \___  exit loss V2^2/2g
                |\____ HGL ______\_|
                |                  ===== reservoir 2
  small pipe d1 |  large pipe d2
 ===============+==================
  • At the entrance, the TEL drops by the entry loss 0.5V12/2g0.5V_1^2/2g and the HGL drops further by V12/2gV_1^2/2g.
  • Along each pipe both lines slope down by hf=fLV2/2gDh_f = fLV^2/2gD; the slope is steeper in the small pipe.
  • At the sudden enlargement, the TEL drops by (V1−V2)2/2g(V_1 - V_2)^2/2g but the HGL rises, since velocity head falls.
  • At the exit, the whole velocity head V22/2gV_2^2/2g is lost; the HGL meets the lower reservoir surface.

✓ Answer checked by Claude Opus 5.5 (high effort)

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