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Department store 30 × 15 m twin 55 W LED

Short answer

45 twin 55W LED luminaires arranged in 9×5 grid provide 316.8 lux. Nine 6A lighting sub-circuits (5 luminaires each) balanced across three phases. Distribution board: 10A TPN MCB incomer, 25A 4P RCCB (100mA), 6A SP MCBs for lights, 4-core 1.5mm² Cu incoming cable.

A department store 30 m × 15 m is illuminated by twin 55W LED luminaries of output 4950 lumens. The lamp being mounted at a height of 3 m from the work plane, the average illumination required is 300 lux. Calculate and arrange the number of luminaries required to be fitted in the department store, assuming the coefficient of utilization to be 0.8 and the maintenance factor to be 0.8. Also design the number of sub-circuit, switches and distribution board, if the supply system is 3-phase, 400V, 50Hz.

Given: store 30 m × 15 m, twin 55 W LED luminaire (110 W per luminaire) giving 4950 lm, Hm = 3 m, E = 300 lux, CU = 0.8, MF = 0.8, supply 400 V, 3-phase, 50 Hz. Assumptions: 4950 lm is the output of one twin luminaire; SHR ≤ 1.5 (spacing ≤ 4.5 m); pf 0.9.

Number of luminaires

Lumen method: N = (E × A) / (φ × UF × MF), where φ is the output of one luminaire.

Area A        = 30 × 15 = 450 m²
φ per luminaire = 4950 lm
Total lumens  = E × A / (UF × MF)
              = 300 × 450 / (0.8 × 0.8)
              = 210938 lm
N             = 210938 / 4950 = 42.61

Rounding up and fitting a regular grid: 9 × 5 = 45 luminaires (9 along the 30 m side, 5 along the 15 m side).

Arrangement and spacing

Spacing along length = 30/9 = 3.33 m
Spacing along width  = 15/5 = 3 m
End spacing (to wall) = half of these
Max spacing = SHR × Hm = 1.5 × 3 = 4.5 m
3.33 m and 3 m ≤ 4.5 m  → OK
Actual E = 45 × 4950 × 0.8 × 0.8 / 450
         = 316.8 lux (≥ 300 lux required)

Layout diagram

Plan 30 m × 15 m (letter = phase of lamp circuit)
+-------------------+
| R R R R R Y Y Y Y |
| R R R B B B B B Y |
| R R Y Y Y Y Y B B |
| Y R R R R R B B B |
| Y Y Y Y B B B B B |
+-------------------+
[DB]  [SB]  <- entrance: DB and switch board
       S S S S ... one switch per sub-circuit

Each light sub-circuit is controlled by one 6 A one-way switch; all switches are grouped on a switch board (SB) next to the entrance, and the DB is mounted beside it.

Sub-circuits

Rule (IS 732 / NEA practice): a light sub-circuit carries at most 10 points and 800 W. Here one luminaire is 110 W, so up to 7 luminaires per sub-circuit. Number of circuits is made a multiple of 3 for phase balance.

CircuitLuminairesLoad (W)Current (A)PhaseMCB
L155502.66R6 A
L255502.66Y6 A
L355502.66B6 A
L455502.66R6 A
L555502.66Y6 A
L655502.66B6 A
L755502.66R6 A
L855502.66Y6 A
L955502.66B6 A

Distribution board design

PhaseCircuitsLoad (W)Current (A)
RL1, L4, L716507.97
YL2, L5, L816507.97
BL3, L6, L916507.97
Total connected load = 4950 W (lighting)
Most loaded phase    = 1650 W
Iph = 1650 / (230 × 0.9) = 7.97 A
Main MCB ≥ 1.25 × 7.97 = 9.96 A → 10 A TPN MCB

DB specification: 4-way-per-phase TPN DB (12 ways in all, spares included) with 10 A TPN MCB as incomer, 25 A 4-pole RCCB (100 mA) for earth-leakage protection, 6 A SP MCBs (B-curve) for light circuits. Incoming cable: 4-core 1.5 mm² Cu PVC (rating 21 A ≥ 10 A), plus earth continuity conductor.

3-phase, 400/230 V, 4-wire supply
        |
   [Energy meter]
        |
   [10 A TPN MCB]
        |
   [25 A 4P RCCB]
        |
==R====Y====B====N== busbars
  |    |    |    |    |
  L1   L2   L3   L4   L5  ...

✓ Answer checked by Claude Opus 5.5 (high effort)

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