- Asked 4/20
- 2071 Bhadra · 8 marks
Factory hall 15 × 12 m metal halide lighting
Short answer
Required 70 W metal halide luminaires: 15, arranged 5×3. Lumen method: φ=6300 lm; lumens needed = 200×180/(0.7×0.6) = 85714 lm; N=13.61 → 15. Three light circuits (6 A MCB, one per phase) on a 6 A TPN MCB incomer with 25 A RCCB.
A factory hall size of 15 m × 12 m is to be illuminated by metal halide lamp of 70 W. Inside the hall, an average illumination of 200 lumen/m² is to be provided on the working plane. The walls and ceiling are brightly painted. Calculate the no. of luminaries required to be fitted in the hall. Draw lay-out diagram showing arrangement of luminaries, switches and distribution board. Decide the light sub-circuits and the supply is 400 V, 3-phase 4 wire system. Assume value for utilization and maintenance factor are 0.7 and 0.6 respectively, the lamp efficiency is 90 lum/watt.
Given: hall 15 m × 12 m, 70 W metal halide lamp at 90 lm/W, E = 200 lm/m², UF = 0.7, MF = 0.6, supply 400 V, 3-phase, 4-wire. Assumptions: high-bay mounting with Hm = 4 m, SHR ≤ 1.5; pf 0.85 with compensated ballast; ballast loss neglected.
Number of luminaires
Lumen method: N = (E × A) / (φ × UF × MF), where φ is the output of one luminaire.
Area A = 15 × 12 = 180 m²
φ per luminaire = 70 W × 90 lm/W = 6300 lm
Total lumens = E × A / (UF × MF)
= 200 × 180 / (0.7 × 0.6)
= 85714 lm
N = 85714 / 6300 = 13.61
Rounding up and fitting a regular grid: 5 × 3 = 15 luminaires (5 along the 15 m side, 3 along the 12 m side).
Arrangement and spacing
Spacing along length = 15/5 = 3 m
Spacing along width = 12/3 = 4 m
End spacing (to wall) = half of these
Max spacing = SHR × Hm = 1.5 × 4 = 6 m
3 m and 4 m ≤ 6 m → OK
Actual E = 15 × 6300 × 0.7 × 0.6 / 180
= 220.5 lux (≥ 200 lux required)
Layout diagram
Plan 15 m × 12 m (letter = phase of lamp circuit)
+-----------+
| R R R R R |
| Y Y Y Y Y |
| B B B B B |
+-----------+
[DB] [SB] <- entrance: DB and switch board
S S S S ... one switch per sub-circuit
Each light sub-circuit is controlled by one 6 A one-way switch; all switches are grouped on a switch board (SB) next to the entrance, and the DB is mounted beside it.
Sub-circuits
Rule (IS 732 / NEA practice): a light sub-circuit carries at most 10 points and 800 W. Here one luminaire is 70 W, so up to 10 luminaires per sub-circuit. Number of circuits is made a multiple of 3 for phase balance.
| Circuit | Luminaires | Load (W) | Current (A) | Phase | MCB |
|---|---|---|---|---|---|
| L1 | 5 | 350 | 1.79 | R | 6 A |
| L2 | 5 | 350 | 1.79 | Y | 6 A |
| L3 | 5 | 350 | 1.79 | B | 6 A |
Distribution board design
| Phase | Circuits | Load (W) | Current (A) |
|---|---|---|---|
| R | L1 | 350 | 1.79 |
| Y | L2 | 350 | 1.79 |
| B | L3 | 350 | 1.79 |
Total connected load = 1050 W (lighting)
Most loaded phase = 350 W
Iph = 350 / (230 × 0.85) = 1.79 A
Main MCB ≥ 1.25 × 1.79 = 2.24 A → 6 A TPN MCB
DB specification: 4-way-per-phase TPN DB (12 ways in all, spares included) with 6 A TPN MCB as incomer, 25 A 4-pole RCCB (100 mA) for earth-leakage protection, 6 A SP MCBs (B-curve) for light circuits. Incoming cable: 4-core 1.5 mm² Cu PVC (rating 21 A ≥ 6 A), plus earth continuity conductor.
3-phase, 400/230 V, 4-wire supply
|
[Energy meter]
|
[6 A TPN MCB]
|
[25 A 4P RCCB]
|
==R====Y====B====N== busbars
| | | | |
L1 L2 L3 ...
Metal halide lamps take 3–5 minutes to reach full output and 10–15 minutes to restrike, so a few LED lamps on a separate circuit are advisable for emergency/escape lighting.
✓ Answer checked by Claude Opus 5.5 (high effort)
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