- Asked 4/20
- 2075 Bhadra · 8 marks
Hall 16 × 12 m LED lighting
Short answer
Mounting height 3 m. N = (300 ×192) / (4950 ×0.64) =20 luminaires in a5 ×4 grid. Distribution board: 6 A TPN MCB incomer, 25 A RCCB, three 6 A SP lighting circuits.
A hall of size 16 m× 12 m is to be illuminated by 55 watt LED lamp. Inside the hall, an average illumination of 300 lumen/m² is to be provided on the working plane. The walls and ceiling are brightly painted. Calculate the no. of luminaries required to be fitted in the hall. Draw lay-out diagram showing arrangement of luminaries, switches and distribution board. Decide the light sub-circuits if the supply is 400 V, 3-phase 4 wire system. Assume value for utilization and maintenance factor are 0.8 and 0.8 respectively, the lamp efficiency is 90 lumen/watt.
Given: hall 16 m × 12 m, E = 300 lm/m², 55 W LED at 90 lm/W, UF = 0.8, MF = 0.8, supply 400 V, 3-phase, 4-wire. Assumptions: mounting height 3 m above working plane, SHR ≤ 1.5, pf 0.9.
Number of luminaires
Lumen method: N = (E × A) / (φ × UF × MF), where φ is the output of one luminaire.
Area A = 16 × 12 = 192 m²
φ per luminaire = 55 W × 90 lm/W = 4950 lm
Total lumens = E × A / (UF × MF)
= 300 × 192 / (0.8 × 0.8)
= 90000 lm
N = 90000 / 4950 = 18.18
Rounding up and fitting a regular grid: 5 × 4 = 20 luminaires (5 along the 16 m side, 4 along the 12 m side).
Arrangement and spacing
Spacing along length = 16/5 = 3.2 m
Spacing along width = 12/4 = 3 m
End spacing (to wall) = half of these
Max spacing = SHR × Hm = 1.5 × 3 = 4.5 m
3.2 m and 3 m ≤ 4.5 m → OK
Actual E = 20 × 4950 × 0.8 × 0.8 / 192
= 330 lux (≥ 300 lux required)
Layout diagram
Plan 16 m × 12 m (letter = phase of lamp circuit)
+-----------+
| R R R R R |
| Y Y Y R R |
| Y Y Y Y B |
| B B B B B |
+-----------+
[DB] [SB] <- entrance: DB and switch board
S S S S ... one switch per sub-circuit
Each light sub-circuit is controlled by one 6 A one-way switch; all switches are grouped on a switch board (SB) next to the entrance, and the DB is mounted beside it.
Sub-circuits
Rule (IS 732 / NEA practice): a light sub-circuit carries at most 10 points and 800 W. Here one luminaire is 55 W, so up to 10 luminaires per sub-circuit. Number of circuits is made a multiple of 3 for phase balance.
| Circuit | Luminaires | Load (W) | Current (A) | Phase | MCB |
|---|---|---|---|---|---|
| L1 | 7 | 385 | 1.86 | R | 6 A |
| L2 | 7 | 385 | 1.86 | Y | 6 A |
| L3 | 6 | 330 | 1.59 | B | 6 A |
Distribution board design
| Phase | Circuits | Load (W) | Current (A) |
|---|---|---|---|
| R | L1 | 385 | 1.86 |
| Y | L2 | 385 | 1.86 |
| B | L3 | 330 | 1.59 |
Total connected load = 1100 W (lighting)
Most loaded phase = 385 W
Iph = 385 / (230 × 0.9) = 1.86 A
Main MCB ≥ 1.25 × 1.86 = 2.32 A → 6 A TPN MCB
DB specification: 4-way-per-phase TPN DB (12 ways in all, spares included) with 6 A TPN MCB as incomer, 25 A 4-pole RCCB (100 mA) for earth-leakage protection, 6 A SP MCBs (B-curve) for light circuits. Incoming cable: 4-core 1.5 mm² Cu PVC (rating 21 A ≥ 6 A), plus earth continuity conductor.
3-phase, 400/230 V, 4-wire supply
|
[Energy meter]
|
[6 A TPN MCB]
|
[25 A 4P RCCB]
|
==R====Y====B====N== busbars
| | | | |
L1 L2 L3 ...
✓ Answer checked by Claude Opus 5.5 (high effort)
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