- 2074 Bhadra · 8 marks
Design procedure: cross and distributary head regulator
Short answer
For cross regulator, compute Qcr=Qp-Qd, crest at d/s bed, waterway from orifice flow, scour and floor by Khosla. Distributary head regulator: sill at distributary bed, waterway from head difference, same scour and floor design. Both need cut-offs, inverted filter, and stone apron.
Write the stepwise design procedure of cross regulator and distributary head regulator with supporting sketches.
A cross regulator is placed across the parent canal d/s of an off-take, and a distributary head regulator is placed at the off-take. Both are gated structures with similar design steps.
Cross regulator
- Data: parent canal discharge , off-take discharge , u/s and d/s FSL, bed levels and widths.
- Discharge through the regulator: .
- Afflux: u/s FSL d/s FSL (usually 0.15 to 0.3 m).
- Crest level: at the d/s bed (or raised 0.3 to 0.5 m if the canal is silty). Provide gates and piers.
- Waterway: from orifice flow, with , or from the weir formula ; provide bays and piers.
- Scour and cut-offs: Lacey's ; d/s cut-off at below the d/s water level and u/s cut-off about .
- Floor: length by Khosla's exit gradient for the maximum static head u/s FSL d/s bed; thickness from uplift.
- Protection works: inverted filter, stone apron.
Distributary head regulator
- Data: distributary discharge, parent FSL, distributary FSL and bed level.
- Sill level: at the distributary bed level (raised 0.3 m to reduce silt entry if needed).
- Waterway: orifice flow, , ; provide bays and piers.
- Cut-offs, floor length, thickness and protection as for the cross regulator, using the head parent FSL distributary bed.
- Alignment: the head regulator is set at an angle of about 60° to 90° to the parent canal, and a cross regulator is placed d/s to hold the water level.
Plan: parent canal ===>===[CR]===>===
\ [HR]
\==> distributary
Section: gates | piers | crest | floor | cut-offs
✓ Answer checked by Claude Opus 5.5 (high effort)
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