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Elementary profile of gravity dam

Short answer

The elementary profile is a right-angled triangle with vertical upstream face and apex at maximum water level. Base width is proportioned from no-tension condition B = H/√(S_c−K) and sliding condition B = H/(μ(S_c−K)), taking the larger value, with K=0 for no uplift or 1 for full uplift.

Define the elementary profile of a gravity dam. How do you proportion the dimensions of an elementary profile if the reservoir is full?

Elementary profile

The elementary profile of a gravity dam is the basic right-angled triangular section with a vertical upstream face, its apex at the maximum water level (zero top width) and the base width BB at the foundation. It is the smallest section that is stable under water pressure, self-weight and uplift, and it is the starting point for the practical profile (which adds crest width and freeboard).

  apex (MWL)
     |\
     | \
   H |  \   d/s face
     |   \
     +----\
       B

Proportioning when the reservoir is full

Let HH = height of water, ScS_c = specific gravity of the dam material, KK = uplift coefficient (fraction of full uplift; K=1K=1 means full uplift at the heel), μ\mu = coefficient of friction, γw\gamma_w = unit weight of water. Per metre length:

  • Weight W=12BHScγwW=\tfrac12 B H S_c\gamma_w at 23B\tfrac23B from the toe (centroid of the triangle)
  • Water thrust P=12γwH2P=\tfrac12\gamma_wH^2 at H/3H/3 above the base
  • Uplift U=12KγwHBU=\tfrac12 K\gamma_w H B at 23B\tfrac23B from the toe

1. No tension (resultant at the lower third point, e=B/6e=B/6): the resultant should cut the base at B/3B/3 from the toe, so moments about the toe give

(W−U)B3=(W−U)2B3−PH3(W-U)\tfrac{B}{3}=(W-U)\tfrac{2B}{3}-P\tfrac{H}{3} 13⋅12γwBH(Sc−K) B=12γwH2⋅H3  ⇒  B=HSc−K\tfrac{1}{3}\cdot\tfrac12\gamma_wBH(S_c-K)\,B=\tfrac12\gamma_wH^2\cdot\tfrac{H}{3}\;\Rightarrow\;B=\frac{H}{\sqrt{S_c-K}}

(With no uplift, K=0K=0 and B=H/ScB=H/\sqrt{S_c}.)

2. Sliding (friction, FS=1FS=1): μ(W−U)≥P\mu(W-U)\ge P

μ⋅12γwBH(Sc−K)≥12γwH2  ⇒  B=Hμ(Sc−K)\mu\cdot\tfrac12\gamma_wBH(S_c-K)\ge\tfrac12\gamma_wH^2\;\Rightarrow\;B=\frac{H}{\mu(S_c-K)}

3. Stress at the toe: with the resultant at the kern, σtoe=2ΣVB=γwH(Sc−K)\sigma_{toe}=\dfrac{2\Sigma V}{B}=\gamma_wH(S_c-K) and the principal stress is σ1=σtoe(1+tan⁡2ϕ)=γwH(Sc−K+1)\sigma_1=\sigma_{toe}(1+\tan^2\phi)=\gamma_wH(S_c-K+1) (it must not exceed the permissible stress).

The base width is taken as the larger of the widths from the no-tension and sliding conditions, if the stress is within the limit. The apex is then raised by adding a crest width and freeboard to get the practical profile.

✓ Answer checked by Claude Opus 5.5 (high effort)

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