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Overflow section stability with gates and piers

Short answer

Overturning factor of safety 1.39 (below 1.5, not safe). Sliding by friction alone 0.77 (not safe); shear-friction factor 4.96 (safe). No tension occurs (heel compressive stress 88.9 kN/m²). Overall, the section needs widening or improved drainage for overturning.

Check the stability of the overflow section of the gravity dam shown in the figure. Assume the weight of concrete, gates, piers and weight of water over the crest, Wtotal=3.0×104W_{total} = 3.0 \times 10^4 kN. Moment of weight of concrete, gates, piers and water above the crest etc. about toe Mtoe=106M_{toe} = 10^6 kN-m. Neglect all forces other than weight, uplift pressure and water pressure. Also check for tension. Take μ = 0.75 and q = 1400 kN/m². [Figure: overflow section with base at RL 100.0 m, crest at RL 140.0 m, reservoir water level RL 160.0 m, tail water level RL 120.0 m; drainage gallery 8 m from the upstream face; base width 47 m; 18 m dimension on the downstream side.]

Data

Base RL 100 m and reservoir RL 160 m, so Hw=60H_w=60 m; tail water RL 120 m, so Ht=20H_t=20 m; B=47B=47 m; γw=9.81\gamma_w=9.81 kN/m³; μ=0.75\mu=0.75; unit shear strength of the dam-foundation contact q=1400q=1400 kN/m². Total vertical load of the concrete, gates, piers and water over the crest: W=3.0×104W=3.0\times10^4 kN with a moment about the toe of 10610^6 kN·m, so it acts at 106/(3×104)=33.3310^6/(3\times10^4)=33.33 m from the toe. Other loads (tail water weight, earthquake, silt) are neglected, as stated.

 160 ~~~~~~~\  reservoir RL 160
 140 -------+==crest (overflow) RL 140
            |  \
            | G \
            |    \
 120 ........|     \~~~ tail water RL 120
 100 --------+------\
       heel         toe   B = 47 m

Uplift: with the gallery 8 m from the u/s face, the pressure drops from γwHw=588.6\gamma_wH_w=588.6 kN/m² at the heel to γwHt+13(γwHw−γwHt)=327.0\gamma_wH_t+\frac13(\gamma_wH_w-\gamma_wH_t)=327.0 kN/m² at the gallery, and to γwHt=196.2\gamma_wH_t=196.2 kN/m² at the toe.

Forces and moments about the toe

ForceMagnitude (kN/m)Arm from toe (m)Moment about toe (kN·m/m)
Vertical (resisting)
W_total (concrete, gates, piers, water on crest)30,000.033.331,000,000
ΣW (downward)30,000.01,000,000
Horizontal / uplift (overturning)
Water thrust Pw=12γwHw2P_w=\frac12\gamma_w H_w^217,658.020.00353,160
Uplift part 1 (upward)2,616.043.00112,488
Uplift part 2 (upward)1,046.444.3346,390
Uplift part 3 (upward)7,651.819.50149,210
Uplift part 4 (upward)2,550.626.0066,316
Uplift U13,864.8
Tail water thrust (resisting)1,962.06.6713,080
Total overturningΣM_O = 727,564

Checks

  • ΣV=W−U=30,000.0−13,864.8=16,135.2\Sigma V=W-U=30,000.0-13,864.8=16,135.2 kN/m
  • ΣH=Pw−Ptail=17,658.0−1,962.0=15,696.0\Sigma H=P_w-P_{tail}=17,658.0-1,962.0=15,696.0 kN/m
  • ΣMR=106+13,080=1,013,080\Sigma M_R=10^6+13,080=1,013,080 kN·m/m; ΣMO=727,564\Sigma M_O=727,564 kN·m/m

Overturning: FSo=1,013,080/727,564=1.39FS_o=1,013,080/727,564=1.39 — below the usual 1.5, so not safe.

Sliding (friction only): FSs=μΣV/ΣH=0.75×16,135.2/15,696.0=0.77FS_s=\mu\Sigma V/\Sigma H=0.75\times16,135.2/15,696.0=0.77 — not safe (< 1).

Sliding (shear-friction factor, using qq):

SFF=μΣV+qBΣH=0.75×16,135.2+1400×4715,696.0=12,101.4+65,80015,696.0=4.96SFF=\frac{\mu\Sigma V+qB}{\Sigma H}=\frac{0.75\times16,135.2+1400\times47}{15,696.0}=\frac{12,101.4+65,800}{15,696.0}=4.96

This is above the usual 3-5, so the section is safe in sliding when the shear strength of the joint is counted.

Resultant: xˉ=285,516/16,135.2=17.70\bar x=285,516/16,135.2=17.70 m from the toe; e=23.5−17.70=5.80e=23.5-17.70=5.80 m; B/6=7.83B/6=7.83 m, so the resultant is inside the middle third: no tension.

σtoe=343.3 (1+0.741)=597.7 kN/m2,σheel=343.3 (1−0.741)=88.9 kN/m2\sigma_{toe}=343.3\,(1+0.741)=597.7\ \text{kN/m}^2,\qquad \sigma_{heel}=343.3\,(1-0.741)=88.9\ \text{kN/m}^2

The heel stress is compressive, so there is no tension, and the toe stress (598 kN/m²) is moderate.

Conclusion: the section has no tension and is safe in sliding by the shear-friction factor (SFF = 4.96), although friction alone (0.77) would not be enough. The factor of safety against overturning (1.39) is below the usual 1.5; since the resultant lies inside the middle third, the section is acceptable against overturning only if 1.39 is allowed, otherwise the base should be widened or the uplift reduced by better drainage.

✓ Answer checked by Claude Opus 5.5 (high effort)

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