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Gravity dam stresses with drainage gallery uplift

Short answer

With crest width 8 m, base 58.25 m, the resisting moment is 2,389,982 kN·m/m and overturning moment 1,424,943 kN·m/m. Maximum vertical stress at the toe is 1506 kN/m², at the heel 100 kN/m². Factor of safety against overturning is 1.68, against sliding 1.12 (μ=0.75).

A concrete gravity dam has the following data: maximum water level = 550.00; bed level = 470.00; RL of top of dam = 554.00; the d/s slope is 0.67 : 1 and starts at RL 545.00; the u/s face is vertical; the centre line of the drainage gallery is 8.0 m from the u/s face. Consider only weight, water pressure and uplift. Calculate the maximum vertical stresses at the toe and heel of the dam. Also calculate the factor of safety against sliding and overturning. Assume 100% uplift pressure at the heel, 50% at the drainage gallery and zero at the toe. Take μ = 0.75.

Data and assumptions

  • Bed RL 470 m, top RL 554 m, so height =84=84 m; MWL 550 m, so Hw=80H_w=80 m; no tail water.
  • U/s face vertical. D/s face vertical from 554 to 545 m, then 0.67 : 1 to the toe, giving a horizontal run of 0.67×75=50.250.67\times75=50.25 m.
  • Crest width is not given; 8 m is assumed, so B=8+50.25=58.25B=8+50.25=58.25 m.
  • γc=24\gamma_c=24 kN/m³ (assumed), γw=9.81\gamma_w=9.81 kN/m³, μ=0.75\mu=0.75.
  • Uplift: 100% of γwHw=784.8\gamma_wH_w=784.8 kN/m² at the heel, 50% (392.4392.4 kN/m²) at the gallery (8 m from the u/s face), zero at the toe.
 554 +---+          crest
 550 |~~~|  MWL  (H_w = 80 m)
     |   |
 545 |   \          d/s slope begins
     | G  \         0.67 : 1
     |     \
 470 +------\
     heel     toe

Forces and moments about the toe

ForceMagnitude (kN/m)Arm from toe (m)Moment about toe (kN·m/m)
Vertical (resisting)
Rectangle 8 × 8416,128.054.25874,944
D/s triangle (50.25 × 75)45,225.033.501,515,038
ΣW (downward)61,353.0ΣM_R = 2,389,982
Horizontal / uplift (overturning)
Water thrust Pw=12γwHw2P_w=\frac12\gamma_w H_w^231,392.026.67837,120
Uplift part 1 (upward)3,139.254.25170,302
Uplift part 2 (upward)1,569.655.5887,244
Uplift part 3 (upward)9,859.133.50330,278
Uplift U14,567.9
Total overturningΣM_O = 1,424,943

Results

  • ΣV=ΣW−U=61,353.0−14,567.9=46,785.1\Sigma V = \Sigma W - U = 61,353.0 - 14,567.9 = 46,785.1 kN/m
  • ΣH=Pw=31,392.0\Sigma H = P_w = 31,392.0 kN/m
  • ΣMR=2,389,982\Sigma M_R = 2,389,982 kN·m/m; ΣMO=1,424,943\Sigma M_O = 1,424,943 kN·m/m

Overturning: FSo=ΣMR/ΣMO=2,389,982/1,424,943=1.68FS_o = \Sigma M_R/\Sigma M_O = 2,389,982/1,424,943 = 1.68 — safe (> 1.5).

Sliding (friction): FSs=μΣV/ΣH=0.75×46,785.1/31,392.0=1.12FS_s = \mu\Sigma V/\Sigma H = 0.75\times46,785.1/31,392.0 = 1.12 — safe (> 1).

Resultant: xˉ=(ΣMR−ΣMO)/ΣV=965,038/46,785.1=20.63\bar x = (\Sigma M_R-\Sigma M_O)/\Sigma V = 965,038/46,785.1 = 20.63 m from the toe; e=B/2−xˉ=29.125−20.63=8.50e = B/2-\bar x = 29.125-20.63 = 8.50 m; B/6=9.71B/6 = 9.71 m — inside the middle third (no tension).

σtoe=ΣVB(1+6eB)=803.2 (1+0.875)=1506.2 kN/m2\sigma_{toe} = \frac{\Sigma V}{B}\left(1+\frac{6e}{B}\right) = 803.2\,(1+0.875) = 1506.2\ \text{kN/m}^2 σheel=803.2 (1−0.875)=100.1 kN/m2\sigma_{heel} = 803.2\,(1-0.875) = 100.1\ \text{kN/m}^2

The toe stress of 1506 kN/m² is well within the usual allowable compressive stress of concrete (about 2500 to 3000 kN/m²; no value is given in the question). The heel stress of 100 kN/m² is compressive, so there is no tension.

Shear and principal stress at the toe (tan⁡ϕd=0.670\tan\phi_d=0.670, p′=0.0p'=0.0 kN/m²):

τtoe=(σtoe−p′)tan⁡ϕd=(1506.2−0.0)×0.670=1009.2 kN/m2\tau_{toe} = (\sigma_{toe}-p')\tan\phi_d = (1506.2-0.0)\times0.670 = 1009.2\ \text{kN/m}^2 σ1,toe=σtoesec⁡2ϕd−p′tan⁡2ϕd=1506.2 (1+0.449)−0.0×0.449=2182.4 kN/m2\sigma_{1,toe} = \sigma_{toe}\sec^2\phi_d - p'\tan^2\phi_d = 1506.2\,(1+0.449) - 0.0\times0.449 = 2182.4\ \text{kN/m}^2

Answer: maximum vertical stress at the toe = 1506 kN/m²; at the heel = 100 kN/m²; factor of safety against overturning = 1.68; against sliding = 1.12. (If the actual crest width differs from 8 m, replace the crest rectangle and recompute with the same table.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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