Skip to main content

Number of jets of Pelton wheel (300 m, 1.5 m³/s)

Short answer

Jet velocity is 73.65 m/s and each 100 mm jet carries 0.5785 m3/s; 1.5 m3/s divided by this gives 2.59, so use 3 jets.

Water is being supplied to a Pelton wheel under a head of 300 m through 100 mm diameter pipes. If the quantity of water supplied to the wheel is 1.50 m³/s, find the number of jets in the wheel. Assume coefficient of velocity is 0.96.

Interpretation

The 100 mm diameter is taken as the diameter of each jet (nozzle outlet). Head H=300H = 300 m, Cv=0.96C_v = 0.96, total Q=1.5 m3/sQ = 1.5\ \text{m}^3/\text{s}.

Velocity of jet

V1=Cv2gH=0.962×9.81×300=73.65 m/sV_1 = C_v\sqrt{2gH} = 0.96\sqrt{2 \times 9.81 \times 300} = 73.65\ \text{m/s}

Discharge through one jet

q=π4d2V1=π4(0.1)2×73.65=0.5785 m3/sq = \frac{\pi}{4}d^2V_1 = \frac{\pi}{4}(0.1)^2 \times 73.65 = 0.5785\ \text{m}^3/\text{s}

Number of jets

n=Qq=1.50.5785=2.59≈3n = \frac{Q}{q} = \frac{1.5}{0.5785} = 2.59 \approx 3

Answer: 3 jets (the next whole number above 2.59).

✓ Answer checked by Claude Opus 5.5 (high effort)

All Hydropower Engineering chapter 7 questions →