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Series operation of two full converters

Short answer

Two single-phase full converters are supplied by separate transformer secondaries and their dc outputs connected in series. The total output is sum of individual voltages; with sequence control, one converter operates at fixed α (0° for rectification, 180° for inversion) while the other is phase-controlled, achieving high voltage and improved power factor.

Describe the series operation of two single phase full converter to obtain high output voltage.

Two single-phase full converters are fed from two separate transformer secondaries and their d.c. outputs are connected in series. This is used for high-voltage d.c. output (for example traction) and, with sequence control, to improve the input power factor and reduce harmonics.

Circuit

              +------------------+
  ~ ---+  S1  |  Full converter 1|--+ +
       |  ))  |  T1 T3 / T4 T2   |  |  Vo1
  pri  |      +------------------+  |
 (one  |                            +----+
 trans-|      +------------------+  |    | load
 former|  S2  |  Full converter 2|--+    | (RLE)
  two  |  ))  |  T1'T3'/T4'T2'   |  |    |
  sec.)|      +------------------+  |    |
  ~ ---+                            +----+
                                       -

Each secondary has rms voltage VsV_s and peak VmV_m. The total output is

Vo=Vo1+Vo2=2Vmπ(cos⁡α1+cos⁡α2)V_o = V_{o1} + V_{o2} = \frac{2V_m}{\pi}(\cos\alpha_1 + \cos\alpha_2)

The maximum output is 4Vmπ\frac{4V_m}{\pi} (both at α=0\alpha = 0).

Rectification mode (power flow a.c. to d.c.)

Converter 1 is kept at α1=0∘\alpha_1 = 0^\circ (output +2Vmπ+\frac{2V_m}{\pi}) and converter 2 is phase-controlled, α2\alpha_2 from 180∘180^\circ down to 0∘0^\circ:

Vo=2Vmπ(1+cos⁡α2)V_o = \frac{2V_m}{\pi}(1 + \cos\alpha_2)

At α2=180∘\alpha_2 = 180^\circ the two outputs cancel (Vo=0V_o = 0); at α2=0∘\alpha_2 = 0^\circ, Vo=4VmπV_o = \frac{4V_m}{\pi}. So the output is varied smoothly from 0 to 4Vmπ\frac{4V_m}{\pi} with power flowing from the a.c. supply to the load.

Inversion mode (power flow d.c. to a.c.)

The load must contain a d.c. source EE of reversed polarity (for example a motor in regenerative braking). One converter is held at α1=180∘\alpha_1 = 180^\circ (full negative voltage, −2Vmπ-\frac{2V_m}{\pi}) and the other is controlled between 0∘0^\circ and 180∘180^\circ:

Vo=2Vmπ(cos⁡α2−1)V_o = \frac{2V_m}{\pi}(\cos\alpha_2 - 1)

so VoV_o ranges from 0 to −4Vmπ-\frac{4V_m}{\pi}; current direction stays the same, so power flows back to the a.c. supply. (In practice the angle is kept below about 165∘165^\circ to allow a margin for commutation.)

Example

With Vs=230V_s = 230 V on each secondary, Vm=325.27V_m = 325.27 V and the maximum d.c. voltage is 4×325.27π=414.1\frac{4 \times 325.27}{\pi} = 414.1 V, twice that of a single full converter (207.1 V), while each thyristor still blocks only Vm=325.3V_m = 325.3 V.

Advantages

  • High output voltage with devices of half the voltage rating.
  • Better input power factor and lower harmonics, because only one converter is phase-controlled at a time.

✓ Answer checked by Claude Opus 5.5 (high effort)

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