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Thyristor V-I, application and opto-isolation

Short answer

The thyristor has reverse blocking (leakage until VBR), forward blocking (leakage until VBO), and ON state (1–2 V). Gate current reduces breakover voltage. In a half-wave controlled rectifier, average Vo = (Vm/(2π))(1+cosα), varying α controls load power. An opto-coupler uses an LED and phototransistor to transfer gate pulses with electrical isolation between control and power circuits.

Explain the V-I characteristics of a power thyristor and illustrate its application in power circuit. How an opto-coupler can be used to isolate the gate signal generator and power circuit?

A thyristor (SCR) is a four-layer P-N-P-N, three-junction (J1,J2,J3J_1, J_2, J_3) semiconductor switch with three terminals: anode (A), cathode (K) and gate (G). It can be turned ON by a small gate pulse when forward biased, but once ON the gate loses control; it turns OFF only when its anode current falls below the holding current.

V-I characteristic

              IA
               ^
               |  |<- ON state (VT = 1-2 V)
               |  |
         IL ---|--|
         IH ---|--+.
               |    `.   Ig2 > Ig1 > Ig=0
               |      `-.___      ___
     -VBR      |            `----'   |
  -----+-------+---------------------+--> VAK
       |       |  forward blocking  VBO
       |       |  (leakage current)
       | reverse blocking
       | (leakage current)
       v reverse avalanche
  1. Reverse blocking mode: cathode is positive with respect to anode. Junctions J1J_1 and J3J_3 are reverse biased and J2J_2 is forward biased, so only a small reverse leakage current flows. If the reverse voltage reaches the reverse breakdown voltage VBRV_{BR}, avalanche breakdown occurs at J1J_1 and J3J_3; the current rises sharply and the device is usually destroyed.
  2. Forward blocking mode: anode is positive and gate is open. J1J_1 and J3J_3 are forward biased but J2J_2 is reverse biased, so only a small forward leakage current flows. The SCR is OFF and blocks the forward voltage.
  3. Forward conduction (ON) mode: if the forward voltage is raised to the forward breakover voltage VBOV_{BO} (with Ig=0I_g = 0), junction J2J_2 breaks down by avalanche and the SCR switches suddenly to the ON state (the negative-resistance jump). The voltage across it drops to about 1 to 2 V and the current is limited only by the load. With gate current, J2J_2 breaks down at a lower voltage: the larger IgI_g, the smaller the breakover voltage (Ig2>Ig1I_{g2} > I_{g1}). In practice the SCR is always turned ON by a gate pulse at a voltage well below VBOV_{BO}.

Application in a power circuit

Example: single-phase half-wave controlled rectifier for a d.c. load (heater, d.c. motor field).

  vs ~ ---+---[SCR]---+
          |           |
          |           R  vo
          |           |
          +-----------+
 vo    __          __
      | \         | \
  ----+--\--------+--\----
     a    pi     2pi+a

The SCR is fired at angle α\alpha in each positive half cycle and turns OFF naturally at π\pi. The average load voltage is

Vo=Vm2π(1+cos⁡α)V_o = \frac{V_m}{2\pi}(1 + \cos\alpha)

so the power to the load is controlled by α\alpha. SCRs are similarly used in full converters, AC voltage controllers (light dimmers, fan regulators), inverters, choppers, and HVDC valves.

Isolation using an opto-coupler

Opto-coupler isolation: the gate signal generator (logic level, grounded to the control circuit) and the power circuit (hundreds of volts, cathode floating) must be electrically separated. An opto-coupler does this with light.

   control side     |      power side
                    |          + Vaux
    R1              |          |
 o--/\/\--+         |          R2
 pulse    |         |          |
         LED ~~~~>  |   photo-transistor
          |  light  |   (C top, E below)
 o--------+         |          |
 GND                |          +------> G
                    |          |
                    |          R3
                    |          |
                    |  Vaux(-) +------> K
  1. The control pulse drives a current through the LED via the current-limiting resistor R1R_1.
  2. The LED emits infrared light, which falls on the phototransistor (or photo-SCR) inside the same package.
  3. The phototransistor turns ON and connects the auxiliary supply VauxV_{aux} (referenced to the cathode) through R2R_2 to the gate, giving gate current. R3R_3 prevents false triggering by noise.
  4. When the pulse ends, the LED is dark, the phototransistor turns OFF and gate current stops.

There is no electrical path between the two sides, so the isolation can withstand a few kV, and noise from the power circuit does not reach the logic circuit.

✓ Answer checked by Claude Opus 5.5 (high effort)

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