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Thyristor V-I, latching/holding, gate signal circuit

Short answer

The characteristic has reverse blocking to V_BR, forward blocking to V_BO, then ON state at 1-2 V; gate current lowers V_BO. Latching current is minimum anode current at turn-on to remain ON after gate removal; holding current is minimum to keep conducting, with IL > IH. A UJT oscillator fires the gate at Vp = ηVBB + VD.

Explain V-I characteristics of a Thyristor and explain the meaning of latching current and holding current. Describe a gate signal generating circuit for firing a Thyristor.

A thyristor (SCR) is a four-layer P-N-P-N, three-junction (J1,J2,J3J_1, J_2, J_3) semiconductor switch with three terminals: anode (A), cathode (K) and gate (G). It can be turned ON by a small gate pulse when forward biased, but once ON the gate loses control; it turns OFF only when its anode current falls below the holding current.

V-I characteristic

              IA
               ^
               |  |<- ON state (VT = 1-2 V)
               |  |
         IL ---|--|
         IH ---|--+.
               |    `.   Ig2 > Ig1 > Ig=0
               |      `-.___      ___
     -VBR      |            `----'   |
  -----+-------+---------------------+--> VAK
       |       |  forward blocking  VBO
       |       |  (leakage current)
       | reverse blocking
       | (leakage current)
       v reverse avalanche
  1. Reverse blocking mode: cathode is positive with respect to anode. Junctions J1J_1 and J3J_3 are reverse biased and J2J_2 is forward biased, so only a small reverse leakage current flows. If the reverse voltage reaches the reverse breakdown voltage VBRV_{BR}, avalanche breakdown occurs at J1J_1 and J3J_3; the current rises sharply and the device is usually destroyed.
  2. Forward blocking mode: anode is positive and gate is open. J1J_1 and J3J_3 are forward biased but J2J_2 is reverse biased, so only a small forward leakage current flows. The SCR is OFF and blocks the forward voltage.
  3. Forward conduction (ON) mode: if the forward voltage is raised to the forward breakover voltage VBOV_{BO} (with Ig=0I_g = 0), junction J2J_2 breaks down by avalanche and the SCR switches suddenly to the ON state (the negative-resistance jump). The voltage across it drops to about 1 to 2 V and the current is limited only by the load. With gate current, J2J_2 breaks down at a lower voltage: the larger IgI_g, the smaller the breakover voltage (Ig2>Ig1I_{g2} > I_{g1}). In practice the SCR is always turned ON by a gate pulse at a voltage well below VBOV_{BO}.

Latching and holding current

  • Latching current (ILI_L): the minimum anode current that must flow through the SCR immediately after it is triggered, while the gate pulse is still present, so that it stays ON after the gate pulse is removed. If the anode current has not reached ILI_L when the gate pulse ends, the SCR turns OFF again.
  • Holding current (IHI_H): the minimum anode current that must keep flowing to hold an already conducting SCR in the ON state (gate open). If the anode current falls below IHI_H, the SCR turns OFF and returns to forward blocking.
  • ILI_L is greater than IHI_H, usually IL≈2I_L \approx 2 to 3 IH3\,I_H. Example: for an SCR with IL=40I_L = 40 mA and IH=15I_H = 15 mA, the gate pulse must last until the anode current reaches 40 mA, but once ON it stays ON until the current drops below 15 mA.

Gate signal generating circuit

UJT relaxation oscillator firing circuit:

   +Vbb ----+-----------+
            |           |
            R          R2
            |           |
            +------- E  B2
            |     UJT
            C           B1
            |           |
   GND -----+          R1 ---> pulse to gate
                        |      (via pulse
   GND -----------------+       transformer)
  1. The capacitor CC charges through RR from VBBV_{BB} with time constant RCRC.
  2. When the capacitor voltage reaches the UJT peak point voltage VP=ηVBB+VDV_P = \eta V_{BB} + V_D (η\eta = intrinsic stand-off ratio), the emitter-B1B_1 path becomes conducting and CC discharges quickly through R1R_1.
  3. The discharge produces a sharp voltage pulse across R1R_1, which is passed to the SCR gate through a pulse transformer.
  4. When the capacitor voltage falls to the valley voltage, the UJT turns OFF and the cycle repeats. The pulse period is T=RCln⁡11−ηT = RC \ln\frac{1}{1-\eta}.
  5. For a.c. circuits, VBBV_{BB} is obtained from the same supply through a rectifier and a Zener clamp, so the first pulse of every half cycle is synchronised with the supply; changing RR changes the firing angle.

✓ Answer checked by Claude Opus 5.5 (high effort)

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