Skip to main content

Thyristor V-I and firing circuit

Short answer

The thyristor V-I curve shows reverse blocking, forward blocking, and forward conduction modes; it turns on by gate pulse below breakover voltage. An RC firing circuit charges a capacitor through a variable resistor; when capacitor voltage reaches gate trigger voltage, the SCR fires, and increasing R delays firing up to about 180 degrees.

Explain the V-I characteristic of a thyristor. Also explain a thyristor firing circuit.

A thyristor (SCR) is a four-layer P-N-P-N, three-junction (J1,J2,J3J_1, J_2, J_3) semiconductor switch with three terminals: anode (A), cathode (K) and gate (G). It can be turned ON by a small gate pulse when forward biased, but once ON the gate loses control; it turns OFF only when its anode current falls below the holding current.

V-I characteristic

              IA
               ^
               |  |<- ON state (VT = 1-2 V)
               |  |
         IL ---|--|
         IH ---|--+.
               |    `.   Ig2 > Ig1 > Ig=0
               |      `-.___      ___
     -VBR      |            `----'   |
  -----+-------+---------------------+--> VAK
       |       |  forward blocking  VBO
       |       |  (leakage current)
       | reverse blocking
       | (leakage current)
       v reverse avalanche
  1. Reverse blocking mode: cathode is positive with respect to anode. Junctions J1J_1 and J3J_3 are reverse biased and J2J_2 is forward biased, so only a small reverse leakage current flows. If the reverse voltage reaches the reverse breakdown voltage VBRV_{BR}, avalanche breakdown occurs at J1J_1 and J3J_3; the current rises sharply and the device is usually destroyed.
  2. Forward blocking mode: anode is positive and gate is open. J1J_1 and J3J_3 are forward biased but J2J_2 is reverse biased, so only a small forward leakage current flows. The SCR is OFF and blocks the forward voltage.
  3. Forward conduction (ON) mode: if the forward voltage is raised to the forward breakover voltage VBOV_{BO} (with Ig=0I_g = 0), junction J2J_2 breaks down by avalanche and the SCR switches suddenly to the ON state (the negative-resistance jump). The voltage across it drops to about 1 to 2 V and the current is limited only by the load. With gate current, J2J_2 breaks down at a lower voltage: the larger IgI_g, the smaller the breakover voltage (Ig2>Ig1I_{g2} > I_{g1}). In practice the SCR is always turned ON by a gate pulse at a voltage well below VBOV_{BO}.

Two important currents on the curve are the latching current ILI_L (minimum current just after turn-on to stay ON) and the holding current IHI_H (minimum current to remain ON); IL>IHI_L > I_H.

Thyristor firing circuit

A firing (triggering) circuit supplies a gate pulse of correct magnitude, width and timing (firing angle α\alpha) and is synchronised with the supply.

Resistance-capacitance (RC) firing circuit (half wave):

      +------- load -------+
      |                    |
   ~ Vs                  A |
      |                  SCR
      |        R      D2   |K
      +---/\/\/\-----|>|-- G
      |     (variable)     |
      |   D1         C     |
      +---|<|---+---||-----+
  1. In the negative half cycle the capacitor CC charges through D1D_1 to −Vm-V_m (upper plate negative).
  2. In the positive half cycle CC charges positively through the variable resistor RR.
  3. When the capacitor voltage reaches the gate trigger voltage VgtV_{gt} plus the drop of D2D_2, gate current flows and the SCR fires.
  4. Increasing RR slows the charging, so firing is delayed. The firing angle can be varied from about 0∘0^\circ to 180∘180^\circ (an R-only circuit gives only 0∘0^\circ to 90∘90^\circ). D2D_2 blocks reverse gate voltage.

A UJT relaxation oscillator or a digital (microcontroller) circuit with a pulse transformer or opto-coupler is used when sharp pulses, wider range and isolation are needed.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Power Electronics chapter 1 questions →