- 2072 Chaitra · 8 marks
Floating car method: flow, journey and running speed
Short answer
Using the moving observer method, N-S flow is 252 veh/h, S-N flow is 260 veh/h. With the likely correct length of 2.55 km, journey speeds are 36.9 km/h (N-S) and 36.9 km/h (S-N), and running speeds are 54.6 km/h (N-S) and 57.0 km/h (S-N).
The following data collected after the floating car method study for a section of road 25.5 km long during the floating car method study. Assuming the equivalency factor of 1, 2 and 3 for each car bus and truck respectively, Calculate the flow in per/hr journey speed and running speed in both direction of flow.
| Direction | Journey time (min) | Journey time (sec) | Stopped delay (min) | Stopped delay (sec) | Opposite: Car | Opposite: Bus | Opposite: Truck | Same direction: Overtaking | Same direction: Overtaken |
|---|---|---|---|---|---|---|---|---|---|
| N-S | 4 | 25 | 1 | 2 | 40 | 2 | 4 | 3 | 1 |
| S-N | 4 | 21 | 1 | 5 | 21 | 2 | 3 | 2 | 3 |
| N-S | 4 | 10 | 1 | 3 | 15 | 1 | 2 | 4 | 2 |
| S-N | 4 | 14 | 1 | 5 | 20 | 5 | 1 | 6 | 1 |
| N-S | 4 | 30 | 1 | 45 | 21 | 3 | 2 | 3 | 3 |
| S-N | 4 | 16 | 1 | 15 | 25 | 2 | 1 | 2 | 2 |
| N-S | 4 | 12 | 1 | 18 | 27 | 4 | 2 | 5 | 2 |
| S-N | 4 | 10 | 1 | 55 | 28 | 1 | 3 | 1 | 1 |
| N-S | 4 | 10 | 1 | 13 | 20 | 3 | 2 | 2 | 3 |
| S-N | 4 | 20 | 1 | 50 | 29 | 2 | 1 | 4 | 3 |
| N-S | 4 | 50 | 1 | 42 | 26 | 1 | 3 | 2 | 2 |
| S-N | 4 | 40 | 1 | 35 | 25 | 3 | 3 | 1 | 1 |
In the floating car (moving observer) method, for each direction the flow is where = vehicles met while running against the stream (in PCU), = vehicles overtaking the test car minus vehicles overtaken by it during the run with the stream, = journey time with the stream and = journey time against the stream. The mean stream journey time is .
Data treatment: PCU factors car 1, bus 2, truck 3 are applied to the opposing counts ( = cars + 2 buses + 3 trucks). Overtaking and overtaken counts are used as numbers of vehicles (types are not given). Section length km as given. Times are converted to seconds.
Data per trip (journey time, stopped delay in s; opposing in PCU)
| N-S trip | Journey | Delay | Opposing | Overtaking | Overtaken |
|---|---|---|---|---|---|
| 1 | 265 | 62 | 56 | 3 | 1 |
| 2 | 250 | 63 | 23 | 4 | 2 |
| 3 | 270 | 105 | 33 | 3 | 3 |
| 4 | 252 | 78 | 41 | 5 | 2 |
| 5 | 250 | 73 | 32 | 2 | 3 |
| 6 | 290 | 102 | 37 | 2 | 2 |
| S-N trip | Journey | Delay | Opposing | Overtaking | Overtaken |
|---|---|---|---|---|---|
| 1 | 261 | 65 | 34 | 2 | 3 |
| 2 | 254 | 65 | 33 | 6 | 1 |
| 3 | 256 | 75 | 32 | 2 | 2 |
| 4 | 250 | 115 | 39 | 1 | 1 |
| 5 | 260 | 110 | 36 | 4 | 3 |
| 6 | 280 | 95 | 40 | 1 | 1 |
Flow in the N-S direction
The vehicles met on the S-N trips form the N-S stream. Averages over 6 trips: PCU, min, min, .
Flow in the S-N direction
Averages: PCU, min, min, .
Journey time, journey speed and running speed
Mean stopped delay: N-S 1.342 min, S-N 1.458 min.
Answer:
| Direction | Flow (veh/h) | Journey speed (km/h) | Running speed (km/h) |
|---|---|---|---|
| N-S | 252 | 369.3 | 546.2 |
| S-N | 260 | 369.2 | 569.7 |
Note: a section of 25.5 km run in about 4.4 minutes implies unrealistic speeds, so the length is probably 2.55 km. Flows are unaffected; the speeds would then be one-tenth of those above (36.9 and 36.9 km/h journey speed, 54.6 and 57.0 km/h running speed).
✓ Answer checked by Claude Opus 5.5 (high effort)
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