- 2067 Mangsir (old course) · 8 marks
Voltage distribution of 3-unit string with guard ring
Short answer
Applying KCL with C1=0.15C and C2=0.05C gives voltage distribution: V1=0.302V, V2=0.3125V, V3=0.3854V. String efficiency = 1/(3×0.3854) ≈ 86.5%.
A 3 unit insulator string is fitted with guard ring. The capacitances of the link pins to metal work and guard ring can be assumed to be 15% and 5% of the capacitance of each unit. Determine the voltage distribution and string efficiency.
With a guard ring, each link pin has two shunt capacitances: one to the earthed metalwork (tower), which takes current away, and one to the guard ring (at line potential), which supplies current. Kirchhoff's current law at each pin gives the voltage distribution.
Data
- 3 identical units, each of capacitance
- Pin-to-metalwork capacitance
- Pin-to-guard-ring capacitance
- Units numbered 1 (top, at cross-arm) to 3 (bottom, at line), with voltages ; line voltage
cross-arm (earth)
| unit 1 (V1)
A ---0.15C--> tower ; <--0.05C-- ring
| unit 2 (V2)
B ---0.15C--> tower ; <--0.05C-- ring
| unit 3 (V3)
line (V) ======= guard ring (V)
KCL at pin A (potential above earth, below ring)
Current in from unit 2 + current from ring = current into unit 1 + current to tower:
KCL at pin B (potential )
Solving
Substitute (1) into (2):
Then :
Hence
Check: .
Voltage distribution
| Unit | Voltage (fraction of ) | Percent |
|---|---|---|
| 1 (top) | 0.3021 (= 29/96) | 30.2% |
| 2 (middle) | 0.3125 (= 30/96) | 31.25% |
| 3 (line end) | 0.3854 (= 37/96) | 38.5% |
String efficiency
For comparison, without the guard ring (, ) the efficiency would be about 82.0%. The guard ring improves the voltage distribution.
Answer: , , ; string efficiency ≈ 86.5%.
✓ Answer checked by Claude Opus 5.5 (high effort)
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