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FDM hierarchy and T carrier system

Short answer

In FDM, voice channels are stacked by SSB: basic group 12 ch 60–108 kHz, supergroup 60 ch 312–552 kHz, mastergroup 300 ch, supermastergroup 900 ch. The T carrier system uses a T1 frame of 193 bits (1 framing + 24×8) every 125 µs, giving 1.544 Mbps. Higher levels: T2 6.312 Mbps (4 T1s), T3 44.736 Mbps (7 T2s), T4 274.176 Mbps (6 T3s).

Explain FDM hierarchy. Describe T carrier system showing the frame structure of T1 level and different multiplexing levels with data rates.

FDM hierarchy

In analogue telephone networks voice channels (0.3–3.4 kHz, 4 kHz slots) are stacked in frequency in steps, by SSB modulation, to form larger and larger groups. The CCITT (ITU-T) hierarchy:

LevelMade fromVoice channelsFrequency bandBandwidth
Voice channel–10–4 kHz4 kHz
Basic group12 channels1260–108 kHz48 kHz
Basic supergroup5 groups60312–552 kHz240 kHz
Basic mastergroup5 supergroups300812–2044 kHz1232 kHz
Supermastergroup3 mastergroups9008516–12388 kHz3872 kHz

(The Bell/AT&T system uses a 600-channel mastergroup of 10 supergroups at 564–3084 kHz, and a 3600-channel jumbo group of 6 mastergroups.)

 12 x voice --[SSB mod]--> GROUP      (12 ch, 60-108 kHz)
  5 x group --[SSB mod]--> SUPERGROUP (60 ch, 312-552 kHz)
  5 x SG    --[SSB mod]--> MASTERGROUP(300 ch)
  3 x MG    --[SSB mod]--> SUPERMASTER(900 ch)

Standard building blocks let equipment from different makers interconnect, and whole groups can be routed together.

T carrier system

The T carrier is the North American digital TDM hierarchy. Each voice channel (DS0) is PCM coded at 8000×8=648000 \times 8 = 64 kbps with µ-law companding.

T1 frame structure:

 1 bit  8 bits  8 bits        8 bits
+-----+-------+-------+-----+--------+
|  F  |  Ch1  |  Ch2  | ... |  Ch24  |
+-----+-------+-------+-----+--------+
<--------- 193 bits in 125 us -------->
F = framing bit
Bits per frame=24×8+1=193 bitsFrame rate=8000 frames/s (T=125 μs)RT1=193×8000=1.544 Mbps\begin{aligned} \text{Bits per frame} &= 24 \times 8 + 1 = 193\ \text{bits} \\ \text{Frame rate} &= 8000\ \text{frames/s}\ (T = 125\ \mu\text{s}) \\ R_{T1} &= 193 \times 8000 = 1.544\ \text{Mbps} \end{aligned}
  • 12 frames form a superframe (D4); the F-bits form an alignment pattern.
  • In frames 6 and 12 the LSB of every channel is robbed for signalling.
  • Line code: AMI/B8ZS on twisted pair.

Multiplexing levels:

24 x DS0 --> [MUX] --> T1  1.544 Mbps (24 ch)
 4 x T1  --> [M12] --> T2  6.312 Mbps (96 ch)
 7 x T2  --> [M23] --> T3  44.736 Mbps (672 ch)
 6 x T3  --> [M34] --> T4  274.176 Mbps (4032 ch)
LevelMade fromVoice channelsBit rateOverhead
DS01 voice channel164 kbps–
DS1 (T1)24 DS0241.544 Mbps8 kbps (framing)
DS2 (T2)4 DS1966.312 Mbps136 kbps
DS3 (T3)7 DS267244.736 Mbps552 kbps
DS4 (T4)6 DS34032274.176 Mbps5.76 Mbps
T2:4×1.544=6.176;  6.312−6.176=0.136 Mbps overheadT3:7×6.312=44.184;  44.736−44.184=0.552 Mbps overheadT4:6×44.736=268.416;  274.176−268.416=5.76 Mbps overhead\begin{aligned} T2 &: 4 \times 1.544 = 6.176;\ \ 6.312 - 6.176 = 0.136\ \text{Mbps overhead} \\ T3 &: 7 \times 6.312 = 44.184;\ \ 44.736 - 44.184 = 0.552\ \text{Mbps overhead} \\ T4 &: 6 \times 44.736 = 268.416;\ \ 274.176 - 268.416 = 5.76\ \text{Mbps overhead} \end{aligned}

The extra overhead at T2, T3 and T4 carries framing, pulse-stuffing control and alarm bits.

✓ Answer checked by Claude Opus 5.5 (high effort)

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