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Power transfer limit vs SIL ratio and length

Short answer

Power transfer limit equals a multiplying factor times V²/Zc. Lower surge impedance (e.g., bundled conductors) raises SIL. The multiplying factor decreases with line length due to stability limits, so capability falls as length increases.

Explain the dependency of power transfer limit to surge impedance ratio & length of transmission line.

Surge impedance loading (SIL) is the power delivered when a lossless line is terminated in its surge impedance Zc=L/CZ_c = \sqrt{L/C}:

SIL=VL2Zc MWSIL = \frac{V_L^2}{Z_c}\ \text{MW}

At SIL the reactive power generated by line capacitance equals that absorbed by inductance, so the voltage is flat along the line.

Dependency on surge impedance

  • SIL ∝1/Zc\propto 1/Z_c. Lowering ZcZ_c (bundled conductors, compact phase spacing, shunt capacitance increase, series compensation) raises SIL and hence the power limit.
  • Typical ZcZ_c: about 400 Ω for single-conductor lines, 250–300 Ω for bundled EHV lines.

Dependency on length

  • Max power P=VsVrZcsin⁡βlP = \frac{V_sV_r}{Z_c\sin\beta l} (lossless line). As length ll increases, sin⁡βl\sin\beta l increases, so power in multiples of SIL falls.
  • Short lines (< 80 km) are limited by thermal rating (about 2.5–3 × SIL); medium lines (80–320 km) by voltage drop (about 1.5–2.5 × SIL); long lines (> 320 km) by stability (about 1 × SIL or less).
Length (km)80160240320480640
Capability / SIL2.752.251.751.351.00.75

So power transfer limit =m.f.(L)×V2/Zc= \text{m.f.}(L) \times V^2/Z_c: it increases with V2V^2, decreases with ZcZ_c, and decreases with line length.

✓ Answer checked by Claude Opus 5.5 (high effort)

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