- 2076 Chaitra · 3+3 marks
8:1 MUX operation; 32:1 MUX from 8:1
Short answer
An 8:1 MUX selects one of 8 inputs I0–I7 using select lines S2S1S0. To build 32:1, use four 8:1 MUXes in the first level covering I0–I31 with S2S1S0. Their outputs feed a fifth 8:1 MUX with selects S4,S3 on its two lowest lines (MSB tied to 0), yielding a 32:1 MUX.
Explain the operation of 8:1 multiplexer with necessary diagrams. Construct 32:1 MUX using only 8:1 MUXs.
Operation of an 8:1 multiplexer
An 8:1 multiplexer selects one of 8 data inputs – and passes it to a single output . The input is chosen by three select lines ().
| 000 | 001 | 010 | 011 | 100 | 101 | 110 | 111 | |
|---|---|---|---|---|---|---|---|---|
| Y |
Internally it has eight 4-input AND gates (each gets one data input and one combination of or their complements) and one 8-input OR gate. Only the AND gate whose select combination is true is enabled.
I0..I7 ---->+---------+
| 8:1 |
| MUX |-----> Y
S2 S1 S0 -->+---------+ (74151)
32:1 MUX using only 8:1 MUXes
A 32:1 MUX needs 5 select lines –.
- Level 1: four 8:1 MUXes (M1–M4) take –, –, –, –. All use .
- Level 2: a fifth 8:1 MUX (M5) selects one of the four outputs. Its select lines are , on its two lower selects and its MSB select tied to 0, so only inputs – of M5 are used.
+-----------+
I0-I7 -->[M1 8:1]-------->| I0 |
I8-I15 -->[M2 8:1]-------->| I1 |
I16-I23 -->[M3 8:1]-------->| I2 M5 |----> Y
I24-I31 -->[M4 8:1]-------->| I3 (8:1) |
0 ---->| I4-I7 |
+-----------+
M1-M4 selects: S2 S1 S0 M5 selects: 0, S4, S3
Total: 5 MUXes of 8:1. Example: gives M3 output , and M5 with passes M3, so .
✓ Answer checked by Claude Opus 5.5 (high effort)
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