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Two reaction theory; determining Xd and Xq

Short answer

The theory splits armature mmf into d- and q-axis components due to saliency. Direct-axis and quadrature-axis synchronous reactances Xd and Xq are determined by the slip test: drive rotor just below synchronous speed with field open, apply reduced stator voltage; Xd = Vmax/Imin, Xq = Vmin/Imax.

Explain two reaction theory of salient pole synchronous machines. Describe a method of determining direct and quadrature axis synchronous reactance of 3 phase synchronous machine.

Two-reaction theory

In a salient-pole machine the air gap is not uniform: it is small along the pole axis (direct axis, d-axis) and large between the poles (quadrature axis, q-axis). So the same mmf produces different flux along the two axes, and the single synchronous reactance of a cylindrical rotor cannot be used. Blondel's two-reaction theory resolves the armature mmf (and the current) into two components, one along each axis, and treats each separately.

  • Id=Isin⁡ψI_d = I\sin\psi: direct-axis component, in quadrature with the emf EE, and acting along the pole axis (magnetising or demagnetising).
  • Iq=Icos⁡ψI_q = I\cos\psi: quadrature-axis component, in phase with EE, acting along the inter-polar axis (cross-magnetising).

Here ψ\psi is the angle between II and EE. Each component produces an armature reaction flux, and so a reactance:

Xd=Xad+Xl,Xq=Xaq+XlX_d = X_{ad} + X_l, \qquad X_q = X_{aq} + X_l

with Xd>XqX_d > X_q because the d-axis has the lower reluctance (typically Xq≈0.6–0.7XdX_q \approx 0.6\text{--}0.7X_d).

Phasor equation (generator)

E⃗=V⃗+I⃗Ra+jI⃗dXd+jI⃗qXq\vec E = \vec V + \vec I R_a + j\vec I_d X_d + j\vec I_q X_q
          E
         /|
   jIdXd/ |     V at angle delta from E
       /  |
      /   |jIqXq
  ---+----+-----> V
   Iq in phase with E
   Id 90 deg behind/ahead

Determination of XdX_d and XqX_q: slip test

  1. Drive the rotor by a prime mover at slightly less than synchronous speed (slip below 1 %), with the field winding open.
  2. Apply a reduced balanced three-phase voltage (about 25 % of rated, with the same phase sequence) to the stator terminals.
  3. The stator rotating field slowly slides past the rotor poles. The effective reluctance varies between the d-axis and q-axis values, so the armature current and terminal voltage oscillate slowly.
  4. Record with an oscillograph (or ammeter and voltmeter readings) the maximum and minimum values:
    • When the field is aligned with the d-axis, the reactance is largest, so the current is minimum and the voltage is maximum.
    • When aligned with the q-axis, the current is maximum and the voltage is minimum.
  5. Then
Xd=VmaxImin,Xq=VminImaxX_d = \frac{V_{max}}{I_{min}}, \qquad X_q = \frac{V_{min}}{I_{max}}

(per phase values; RaR_a is small and neglected).

 Test connections
  3-phase reduced V --> stator
  field winding: OPEN (voltmeter across it
                 shows induced emf pulsating)
  prime mover: speed just below Ns

XdX_d is also found from the open-circuit and short-circuit characteristics (Xd=VocIscX_d = \frac{V_{oc}}{I_{sc}} at the same field current, unsaturated). XqX_q by this test is typically 60 to 70 % of XdX_d.

✓ Answer checked by Claude Opus 5.5 (high effort)

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