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GMR for inductance vs capacitance

Short answer

For inductance, GMR uses r' = 0.7788r to account for internal magnetic flux; for capacitance, GMR uses the actual outer radius r because the electric field inside is zero. Thus inductance GMR is smaller than capacitance GMR.

How does the GMR for inductance calculation differ from the GMR for capacitance calculation? Explain.

The GMR (self-GMD) used in line parameter calculations is different for inductance and capacitance because inductance depends on the magnetic flux, which exists inside the conductor too, while capacitance depends on the electric field, which exists only outside the conductor.

GMR for inductance

  • Current flows through the whole cross-section, so there is magnetic flux inside the conductor as well as outside.
  • The internal flux linkage (μ0I/8π\mu_0 I/8\pi per metre) is included by replacing the actual radius rr with a smaller fictitious radius:
r′=r e−1/4=0.7788 rr' = r\,e^{-1/4} = 0.7788\,r
  • For a stranded or bundled conductor, the self-GMD uses r′r' for each strand: DsL=(r′⋅D12⋯D1n⋯ )1/n2D_{sL} = (r' \cdot D_{12} \cdots D_{1n} \cdots)^{1/n^2}; for a 2-bundle, DsL=r′dD_{sL} = \sqrt{r'd}.

GMR for capacitance

  • Charge resides on the surface of a conductor; the electric field inside a conductor is zero.
  • So there is no "internal" term and the actual outer radius rr is used: DsC=(r⋅D12⋯ )1/n2D_{sC} = (r \cdot D_{12} \cdots)^{1/n^2}; for a 2-bundle, DsC=rdD_{sC} = \sqrt{rd}.

Comparison

PointInductance GMRCapacitance GMR
Field involvedMagneticElectric
Field inside conductorPresentZero
Radius usedr′=0.7788rr' = 0.7788rrr
Solid conductor0.7788r0.7788rrr
2-bundle0.7788r d\sqrt{0.7788r\,d}r d\sqrt{r\,d}
ValueSmallerLarger

Example: for r=1r = 1 cm, GMR for inductance =0.7788= 0.7788 cm, while for capacitance it is 1 cm. The mutual GMD between phases is the same for both calculations.

✓ Answer checked by Claude Opus 5.5 (high effort)

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