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GMR of stranded vs solid conductor

Short answer

For a 7-strand conductor with strand radius r, overall radius is 3r. Stranded GMR = 2.1767r, solid GMR of same diameter = 0.7788*3r = 2.3364r. The stranded GMR is about 7% lower due to air gaps reducing effective conducting cross-section, increasing inductance compared to a solid conductor.

With a suitable example show that the geometric mean radius of a stranded conductor is lower than that of a solid conductor of the same overall diameter.

The geometric mean radius (GMR) of a conductor is the radius of a fictitious thin tube that has the same internal plus external flux linkage as the real conductor. For a solid round conductor of radius RR, GMR=r′=e−1/4R=0.7788RGMR = r' = e^{-1/4}R = 0.7788R. A stranded conductor of the same overall diameter contains air gaps between strands, so its current is spread over less metal and its effective GMR is smaller.

Example: 7-strand conductor

Take a 7-strand conductor, each strand of radius rr: one central strand and six touching strands around it. Overall radius R=3rR = 3r.

        (2)   (3)
     (7)   (1)   (4)      1 = centre strand
        (6)   (5)         ring radius = 2r

Distances between strand centres:

Pair typeDistanceOrdered pairs
Centre to outer2r2r12
Adjacent outers2r2r12
Outer to next-but-one23r2\sqrt{3}r12
Outer to opposite4r4r6
Self (r′r')0.7788r0.7788r7

With n=7n = 7 strands there are n2=49n^2 = 49 terms:

Ds=[(0.7788r)7(2r)24(23r)12(4r)6]1/49=2.1767 r\begin{aligned} D_s &= \left[(0.7788r)^7 (2r)^{24} (2\sqrt{3}r)^{12} (4r)^6\right]^{1/49} \\ &= 2.1767\,r \end{aligned}

Solid conductor of the same overall diameter

GMRsolid=0.7788×3r=2.3364 rGMR_{solid} = 0.7788 \times 3r = 2.3364\,r

Comparison

Ds, strandedGMRsolid=2.1767r2.3364r=0.932\frac{D_{s,\,stranded}}{GMR_{solid}} = \frac{2.1767r}{2.3364r} = 0.932

So the 7-strand conductor has a GMR about 7% smaller than a solid conductor of the same diameter.

Why: the GMR depends on the actual cross-section that carries current. Stranding leaves air gaps, so the current-carrying material sits in a smaller effective area. A smaller GMR means the stranded conductor has a slightly higher inductance (L=2×10−7ln⁡(D/Ds)L = 2\times10^{-7}\ln(D/D_s)) than a solid conductor of the same outer diameter.

Answer: Ds=2.1767rD_s = 2.1767r (stranded) < 2.3364r2.3364r (solid).

✓ Answer checked by Claude Opus 5.5 (high effort)

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