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Design of transformer core

Short answer

Core design fixes net iron area Ai = φm/Bm with φm = Et/(4.44f). Limb is stepped to fill the circular winding; stacking factor ≈0.9; yoke area 15–20% larger than limb for hot-rolled steel. Window area derived from output equation.

Discuss in brief about the design of core of transformer.

Core design fixes the net iron area, the shape of the limb section, the stampings, and the yoke, so that the flux ϕm\phi_m is carried at the chosen flux density with low loss and low cost.

1. Net iron area

From Et=KQE_t = K\sqrt{Q}:

ϕm=Et4.44f,Ai=ϕmBm\phi_m = \frac{E_t}{4.44f},\qquad A_i = \frac{\phi_m}{B_m}

BmB_m is chosen according to the steel: about 1.1–1.45 Wb/m² for hot-rolled, 1.35–1.75 Wb/m² for CRGO.

2. Shape of limb section

Windings are circular, so the limb is made stepped to fill the circle of diameter dd:

Core sectionNet area AiA_iLargest stamping aa
Square0.45d20.45d^20.71d0.71d
Cruciform (2-step)0.56d20.56d^20.85d0.85d
3-stepped0.60d20.60d^20.90d0.90d
4-stepped0.62d20.62d^20.93d0.93d

(stacking factor 0.9). More steps use the circle better and shorten the mean turn, but increase labour. Square and cruciform cores are used for small transformers; 3 to 7 steps for large ones.

3. Stampings and stacking

  • Thin silicon-steel laminations (0.35 mm or less), insulated by varnish or oxide, to reduce eddy loss.
  • Stacking factor (net/gross area) ≈ 0.9.
  • Joints are staggered (overlapped) or mitred at 45° (for CRGO) to reduce reluctance and loss at the corners.
  • Large cores have cooling ducts between packets.

4. Yoke

  • With hot-rolled steel, yoke area is made 15–20% larger than limb area to lower yoke flux density, loss and magnetising current.
  • Yoke is usually rectangular: depth Dy=aD_y = a, height Hy=Agy/DyH_y = A_{gy}/D_y.
  • With CRGO, yoke area is equal to limb area (stepped yoke).

5. Window

The output equation gives the window area, Aw=Q/(2.22 or 3.33 fBmδKwAi×10−3)A_w = Q/(2.22 \text{ or } 3.33\,fB_m\delta K_wA_i\times10^{-3}), with Hw/WwH_w/W_w = 2 to 4. The core frame then follows: D=d+WwD = d + W_w, H=Hw+2HyH = H_w + 2H_y, W=2D+aW = 2D + a (3-phase) or D+aD + a (1-phase).

✓ Answer checked by Claude Sonnet 5.5

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