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Double mass curve, station X and 18 stations

Short answer

A double mass curve shows a slope change after 1959, so the record is inconsistent with a regime change in 1960. The adjusted mean annual rainfall for 1952–1970 under the changed regime is 24.9 cm.

The annual rainfall at station X and the average annual rainfall at 18 surrounding stations are given below. Check the consistency of the record at station X and determine the year in which a change in regime has occurred. Determine the average annual rainfall for the period 1952-1970 for the changed regime.

YearStation X (cm)18-stations' average (cm)
195230.522.8
195338.935
195443.730.2
195532.227.4
195627.425.2
19573228.2
195849.336.1
195928.418.4
196024.625.1
196121.823.6
196228.233.3
196317.323.4
196422.336
196528.431.2
196624.123.1
196726.923.4
196820.623.1
196929.533.2
197028.426.4

A double mass curve plots the cumulative rainfall of station X against the cumulative average rainfall of the 18 base stations. A change in slope shows an inconsistency.

Step 1: Cumulative values

YearX (cm)Base avg (cm)Cum. baseCum. X
195230.522.822.830.5
195338.93557.869.4
195443.730.288.0113.1
195532.227.4115.4145.3
195627.425.2140.6172.7
19573228.2168.8204.7
195849.336.1204.9254.0
195928.418.4223.3282.4
196024.625.1248.4307.0
196121.823.6272.0328.8
196228.233.3305.3357.0
196317.323.4328.7374.3
196422.336364.7396.6
196528.431.2395.9425.0
196624.123.1419.0449.1
196726.923.4442.4476.0
196820.623.1465.5496.6
196929.533.2498.7526.1
197028.426.4525.1554.5

Step 2: Plot and slopes

Plotting cum. X (y-axis) against cum. base average (x-axis), the points follow one straight line up to 1959 and another, flatter line afterwards.

  • Slope before the break (to 1959): Ma=282.4223.3=1.265M_a = \dfrac{282.4}{223.3} = 1.265
  • Slope after the break (1960-1970): Mc=272.1301.8=0.902M_c = \dfrac{272.1}{301.8} = 0.902

The slopes differ, so the record of station X is not consistent. The change in regime occurred in 1960 (the break appears at the 1959-60 point).

Step 3: Adjust to the changed (present) regime

Pcx=Px×McMa=Px×0.9021.265=0.713 PxP_{cx} = P_x \times \frac{M_c}{M_a} = P_x \times \frac{0.902}{1.265} = 0.713\,P_x

Adjusted total for 1952-1959 =0.7129×282.4=201.3= 0.7129 \times 282.4 = 201.3 cm; the total of 1960-1970 is unchanged =272.1= 272.1 cm.

Pˉ1952−70=201.3+272.119=24.92 cm\bar P_{1952-70} = \frac{201.3 + 272.1}{19} = 24.92\ \text{cm}

Answer: Record is inconsistent; change in regime in 1960; mean annual rainfall for 1952-1970 under the changed regime = 24.9 cm (compared with the unadjusted mean of 29.2 cm).

✓ Answer checked by Claude Sonnet 5.5

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