Skip to main content

Techniques for average depth of rainfall

Short answer

Average rainfall depth is determined by arithmetic mean (sum divided by number of gauges), Thiessen polygon method (area-weighted average using polygon areas), and isohyetal method (averaging between rainfall contours, most accurate, especially in hilly regions).

Describe various techniques used to determine the average depth of rainfall over a river catchment area.

The average depth of rainfall over a catchment is needed because rain gauges record only point values, while runoff and hydropower flow depend on rainfall over the whole area. The three standard techniques are given below.

Methods of finding mean precipitation over an area

1. Arithmetic mean method

Pˉ=P1+P2+⋯+PNN\bar{P} = \frac{P_1 + P_2 + \dots + P_N}{N}

Simple; good only for flat areas with uniformly spread gauges and small rainfall variation.

2. Thiessen polygon method

  • Plot stations on the map and join adjacent stations by straight lines to form triangles.
  • Draw perpendicular bisectors of these lines; they form a polygon around each station.
  • Measure the polygon area AiA_i inside the catchment for each station.
Pˉ=∑PiAi∑Ai\bar{P} = \frac{\sum P_i A_i}{\sum A_i}

Accounts for uneven gauge spacing; can use stations just outside the catchment. Does not consider orography; polygons must be redrawn if a gauge is added or removed.

3. Isohyetal method

  • Draw isohyets (lines of equal rainfall) by interpolating between station values.
  • Measure the area aia_i between successive isohyets PiP_i and Pi+1P_{i+1}.
Pˉ=∑ai(Pi+Pi+12)∑ai\bar{P} = \frac{\sum a_i \left(\frac{P_i + P_{i+1}}{2}\right)}{\sum a_i}

Most accurate, especially in hilly areas like Nepal, as the analyst can use knowledge of topography; but needs skill and a dense network.

  Isohyets (mm)          Thiessen polygons
   ___80___               +-----+-----+
  /  _60_  \              |  A  |  B  |
 |  / 40 \  |             |  *  |  *  |
  \ \____/ /              +--+--+--+--+
   \______/                  | C *  |
                             +------+
MethodAccuracyEffort
Arithmetic meanLowLeast
Thiessen polygonMediumMedium
IsohyetalHighMost

Example (Thiessen): stations with 80, 70, 90 mm over areas 100, 150, 80 km² give Pˉ=(8000+10500+7200)/330=77.9\bar{P} = (8000 + 10500 + 7200)/330 = 77.9 mm, while the arithmetic mean is 80 mm.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Hydro Power chapter 2 questions →