- 2081 Chaitra · 3+3 marks
Thiessen polygon method with rainfall data
Short answer
The Thiessen polygon method weights each rain gauge's rainfall by the area of its polygon, formed by perpendicular bisectors between stations. For the given data, average rainfall = (Σ P_i A_i) / Σ A_i = 33500 / 450 = 74.44 mm ≈ 74.4 mm.
a) Explain the Thiessen polygon method for estimating the average rainfall over a catchment area. b) The following data were obtained from a rainfall event. Determine the average rainfall over the catchment using the Thiessen polygon method.
| Rainfall Station | A | B | C | D |
|---|---|---|---|---|
| Area (km²) | 100 | 150 | 80 | 120 |
| Rainfall (mm) | 80 | 70 | 90 | 65 |
a) Thiessen polygon method
The Thiessen polygon method gives the average rainfall by weighting each station's rainfall by the area it represents. It assumes the rainfall at any point equals that at the nearest gauge.
Procedure:
- Plot all rain gauge stations (inside and near the catchment) on a map of the catchment.
- Join adjacent stations by straight lines to form a network of triangles.
- Draw perpendicular bisectors of each side; they meet to form a polygon around each station.
- Measure (by planimeter or GIS) the area of each polygon inside the catchment boundary.
- Compute:
+-------+--------+
| A | B | * = rain gauge
| * | * | lines = perpendicular
+---+---+----+---+ bisectors
| C * |
+--------+
Merits: allows for uneven gauge spacing. Demerits: ignores orographic effects; polygons must be redrawn when the network changes.
b) Numerical
| Station | Area (km²) | Rainfall (mm) | |
|---|---|---|---|
| A | 100 | 80 | 8000 |
| B | 150 | 70 | 10500 |
| C | 80 | 90 | 7200 |
| D | 120 | 65 | 7800 |
| Total | 450 | 33500 |
Answer: Average rainfall over the catchment ≈ 74.4 mm.
✓ Answer checked by Claude Opus 5.5 (high effort)
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