- 2071 Magh · 6 marks
Fuse and contactor ratings for induction motor
Short answer
For a 15kW, 415V motor with eta=0..9, pf=0.85: full-load current =27.28A. Select 63A gG HRC fuse (withstands 163.7A starting for 10s), 32A AC-3 contactor, and thermal overload relay set at 28A. Ensure fuse let-through I²t within contactor withstand for type-2 coordination.
An induction motor is required to protect through a fuse and contactor. Suggest a suitable guide line for selection of ratings of fuse and contactor. State any assumptions you make.
Assumptions: 3-phase squirrel-cage induction motor, 15 kW, 415 V, 50 Hz, efficiency 90 %, power factor 0.85, direct-on-line (DOL) starting, starting current 6 × full-load for up to 10 s, prospective fault current at motor control centre 25 kA. The scheme is fuse (short-circuit protection) + contactor (switching) + thermal overload relay (overload protection).
415 V ─[HRC fuse]─[Contactor]─[O/L relay]─ M
short-ckt switching overload
Step 1: Full-load current
I_FL = P / (√3 · V · η · cosφ)
= 15 000 / (√3 × 415 × 0.90 × 0.85)
= 27.28 A
Starting current = 6 × 27.28 = 163.7 A for ~10 s
Step 2: Fuse selection guidelines
- Type: motor-rated HRC fuse (aM or gM) or time-delay gG fuse, because it must not melt on starting current.
- Rating: for DOL start, about 2–2.5 × I_FL for gG fuses → 54.6–68.2 A. Choose 63 A gG HRC (or a 32 A/40 A aM fuse).
- Check starting: the pre-arcing time of the chosen fuse at 163.7 A must be greater than the starting time (10 s) with margin, also allowing for repeated starts.
- Breaking capacity: must exceed the prospective fault current (25 kA); LV HRC fuses with 80 kA are suitable.
- Back-up to contactor: the fuse must clear all currents above the contactor's breaking capacity, and its cut-off current/I²t must be within the contactor's short-circuit withstand (type-2 coordination as per IEC 60947-4-1).
- Overload protection is not expected from the fuse.
Step 3: Contactor selection guidelines
- Utilisation category: AC-3 (starting squirrel-cage motors, switching off while running).
- Rated operational current Ie (AC-3) ≥ I_FL at 415 V → choose a 32 A AC-3 contactor (≥ 27.28 A).
- Making/breaking capacity: AC-3 contactor makes 10 × Ie (320 A) and breaks 8 × Ie (256 A), so it can make the 163.7 A starting current and break locked-rotor current.
- Coil voltage suited to control supply (230 V AC or 110 V AC/24 V DC) and number of auxiliary contacts for control/interlocks.
- Electrical and mechanical life suitable for number of operations per hour.
Step 4: Overload relay
Thermal (bimetal) relay with range including I_FL, set at 1.0–1.05 × I_FL ≈ 27.3–28.6 A, class 10 trip (operates within 10 s at 7.2 × setting), with single-phasing protection.
Coordination: overload relay curve protects for currents up to about 8–10 × I_FL; above the crossover point the fuse operates first, protecting the contactor.
Answer (for assumed motor): I_FL = 27.28 A; fuse ≈ 63 A gG HRC (or 40 A aM); contactor 32 A AC-3; overload relay set ≈ 28 A.
✓ Answer checked by Claude Opus 5.5 (high effort)
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