- 2069 Chaitra · 10 marks
Intermediate beam design for BM and deflection
Short answer
T-beam with effective flange width 1883 mm. Neutral axis in flange (M_u = 159.90 kN·m). Required A_st = 1009 mm² (4-20 mm bars); deflection safe with L/d = 11.1 << 32.
A floor consists of 125 mm thick RC slab, integrally connected with the beam as shown in figure. Design an intermediate beam for BM and deflection if the floor is subjected to live load of 4 kN/m and floor finishes of 0.7 kN/m. [Figure: floor plan with one-brick-thick wall at the edge; slab spans between parallel beams (dashed lines) with 4 x 4 m panels; beam span 5 m]
Assumptions: M20 and Fe415; beam simply supported with effective span m; slab panels 4 m x 4 m, so an intermediate beam carries slab load from 2 m on each side (width 4 m); beam web mm, overall depth mm, cover 50 mm, so mm. The slab and beam act together as a T-beam.
Step 1: Loads per metre run of beam
Step 2: Bending moment
Step 3: Effective flange width (IS 456 cl. 23.1.2, T-beam)
Step 4: Position of neutral axis. Moment capacity when :
So ; design as a rectangular beam of width .
Step 5: Tension steel
Minimum steel mm is satisfied. Provide 4-20 mm dia ( mm).
Step 6: Deflection check (IS 456 cl. 23.2). , so the flange factor (Fig. 6) is 0.8. For flanged beams, the steel percentage for Fig. 4 is based on :
The beam is safe in deflection. (Shear: kN; stirrups are designed separately.)
Answer: T-beam, mm, mm, mm; mm (4-20 mm bars); safe in deflection.
✓ Answer checked by Claude Opus 5.5 (high effort)
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