- 2065 Kartik (old course) · 12 marks
RC wall footing, 1000 kN total load
Short answer
For 1 m length of wall, required width 1.85 m including 10% footing weight. Factored pressure 202.7 kN/m2 gives Mu=60.87 kNm/m; provide depth 375 mm, main steel 10 mm @ 140 mm c/c and distribution 8 mm @ 110 mm c/c.
Design a RC concrete spread footing of an RC wall having 4 m length and 300 mm width. Total load on wall is equal to 1000 kN at service state. Take M20 and Fe415 grades of concrete and steel respectively, and safe bearing capacity of soil = 150 kN/m.
Data and assumptions
- Wall 300 mm thick and 4 m long carrying a total service load of 1000 kN, so the load per metre run is kN/m. M20 concrete, Fe415 steel, kN/m². The footing is designed for a 1 m length of wall. Cover 50 mm.
Width of footing
(10% is added for the weight of the footing and backfill.)
Factored pressure and bending moment
kN/m, kN/m² Projection beyond the wall face mm.
Depth
The depth is governed by one-way shear at from the wall face (checked below); trial mm, mm (conservative). Flexure check: kN·m kN·m, so the depth is adequate and the section is under-reinforced.
Reinforcement
mm²/m from (minimum 0.12% of = 450 mm²/m). Adopt 548 mm²/m → provide 10 mm @ 140 mm c/c across the width (561 mm²/m, ). Distribution steel along the wall (0.12% of ) = 450 mm²/m → 8 mm @ 110 mm c/c (457 mm²/m).
Check for shear
kN/m; MPa < MPa (M20, , Table 19). Safe.
Development length
mm; available length mm. Satisfied.
Detailing
SECTION ACROSS WALL
| wall 300 |
| |
_____| |_____
| | D = 375 mm
|_______________________|
o o o o o o o o o o o o <- 10 mm @ 140 c/c
<---------- 1.85 m ------->
Distribution bars of 8 mm @ 110 mm c/c are tied above the main bars, parallel to the wall.
Answer: Strip footing 1.85 m wide and 375 mm thick; main bars 10 mm @ 140 mm c/c across the wall, distribution bars 8 mm @ 110 mm c/c.
✓ Answer checked by Claude Opus 5.5 (high effort)
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